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angela210793
 2 years ago
I need some help :S
angela210793
 2 years ago
I need some help :S

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angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty} [\sqrt[3]{n ^{2}}/n+1]\]

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0@Ishaan94 Are you asking me? O.o...idk....i think it is inifinite/infinite =udefined..IDK :S

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3\[\large\frac{\sqrt[3]{\frac{n^2}{n^3}}}{1 + \frac1n}\]

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0Huh???? I didn't get it AT ALL Ishaan...exaplin it please

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3Divide and Multiply by n.

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0Ishaan can u draw it step by step please

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3I thought apoorv was doing it.

m_charron2
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1334846528832:dw

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3\[\Large \frac{\frac{\sqrt[3]{n^2}}n}{\frac{1+n}n}\]

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1My tab "Aw, Snapped" me :'( (lost my labor *sniff sniff*) ^^what Ishaan said.

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0@Ishaan94 would I sound way too dumb if i told you that I STILL don't get it O.o

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Am I only one who this that the limit is \[ \lim_{x \rightarrow \infty} \frac{\sqrt[3]{n ^{2}}}{n}+1 \]

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1HOW? then what were we writing? And why did Angela not correct us?

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0@FoolForMath it is not like that..it is dw:1334846830006:dw

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3dw:1334846790537:dwWhy can't I draw better?!?!?!

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Your latex is misleading.

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3seems like rockstart's gonna rock us now.

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3Yes. Yes. Do it as apoorv says.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0@apoorvk: That's not true.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1Yayy yayy.. @rockstar111 baba's here :p

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0If \(n \to \infty \) then \(\frac 1n \to 0\).

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1comparing two infinities is blasphemy alright :/ But then, how do I express myself?

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Okay it's specious.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0No need to write in terms of infinity, just use the limits and show the answer.

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3Like the way FoolForMath did.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1I am sure @angela210793 has gone crazy by now.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1334847232658:dw

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0I am not saying that your way is incorrect, I think it might be accepted in some places.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0but that is how I would do this one.

m_charron2
 2 years ago
Best ResponseYou've already chosen the best response.0to be honest, I wouldn't blame her from spraining a brain muscle after all this

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0I don't mean to confuse.

m_charron2
 2 years ago
Best ResponseYou've already chosen the best response.0rigor is important as well, so I get your drift :)

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.3She left :/ I won't be a good professor/teacher.

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.0I didn't leave....mozilla froze.....and thank you all...:))) (Idk whom to give a medal now :S)
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