angela210793
I need some help :S



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angela210793
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\[\lim_{x \rightarrow \infty} [\sqrt[3]{n ^{2}}/n+1]\]

Ishaan94
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Is it Zero?

angela210793
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@Ishaan94 Are you asking me? O.o...idk....i think it is inifinite/infinite =udefined..IDK :S

Ishaan94
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\[\large\frac{\sqrt[3]{\frac{n^2}{n^3}}}{1 + \frac1n}\]

angela210793
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Huh???? I didn't get it AT ALL Ishaan...exaplin it please

angela210793
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explain*

Ishaan94
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Divide and Multiply by n.

angela210793
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Ishaan can u draw it step by step please

Ishaan94
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I thought apoorv was doing it.

m_charron2
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dw:1334846528832:dw

Ishaan94
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\[\Large \frac{\frac{\sqrt[3]{n^2}}n}{\frac{1+n}n}\]

apoorvk
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My tab "Aw, Snapped" me :'( (lost my labor *sniff sniff*)
^^what Ishaan said.

angela210793
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@Ishaan94 would I sound way too dumb if i told you that I STILL don't get it O.o

apoorvk
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No.

FoolForMath
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Am I only one who this that the limit is \[ \lim_{x \rightarrow \infty} \frac{\sqrt[3]{n ^{2}}}{n}+1 \]

apoorvk
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HOW? then what were we writing? And why did Angela not correct us?

angela210793
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@FoolForMath it is not like that..it is dw:1334846830006:dw

Ishaan94
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dw:1334846790537:dwWhy can't I draw better?!?!?!

FoolForMath
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Your latex is misleading.

Ishaan94
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seems like rockstart's gonna rock us now.

FoolForMath
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lol

apoorvk
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dw:1334846742289:dw

apoorvk
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dw:1334846901905:dw

Ishaan94
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Yes. Yes. Do it as apoorv says.

FoolForMath
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@apoorvk: That's not true.

apoorvk
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Yayy yayy.. @rockstar111 baba's here :p

FoolForMath
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If \(n \to \infty \) then \(\frac 1n \to 0\).

apoorvk
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I am wrong? \(o.O)/_

apoorvk
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thats.what.i.did.

apoorvk
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comparing two infinities is blasphemy alright :/ But then, how do I express myself?

FoolForMath
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Okay it's specious.

FoolForMath
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No need to write in terms of infinity, just use the limits and show the answer.

Ishaan94
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Like the way FoolForMath did.

apoorvk
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I am sure @angela210793 has gone crazy by now.

FoolForMath
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dw:1334847232658:dw

FoolForMath
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I am not saying that your way is incorrect, I think it might be accepted in some places.

FoolForMath
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but that is how I would do this one.

Ishaan94
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@angela210793 ????

m_charron2
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to be honest, I wouldn't blame her from spraining a brain muscle after all this

FoolForMath
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I don't mean to confuse.

m_charron2
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rigor is important as well, so I get your drift :)

Ishaan94
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She left :/
I won't be a good professor/teacher.

FoolForMath
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Thanks @m_charron2

angela210793
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I didn't leave....mozilla froze.....and thank you all...:)))
(Idk whom to give a medal now :S)