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An LR circuit contains a battery hooked up to an inductor and a resistor in series. A switch effectively removes the battery from the circuit. The switch is initially closed. Immedeiately after the switch is opened, the voltage at location B is...
 one year ago
 one year ago
An LR circuit contains a battery hooked up to an inductor and a resistor in series. A switch effectively removes the battery from the circuit. The switch is initially closed. Immedeiately after the switch is opened, the voltage at location B is...
 one year ago
 one year ago

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elica85Best ResponseYou've already chosen the best response.0
equal to, higher than, or lower than the voltage at location A?
 one year ago

ramkrishnaBest ResponseYou've already chosen the best response.0
higher than the voltage at location A because inductor opposes the change.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.1
@ramkrishna is right about this in the most commonest sense. No offence@ramakrishna. But if you look at it from the point of view of pure physics, its wrong. Because an inductor is just a piece of wire. There cannot be a "potential difference" between the ends of a piece of metallic wire, remember!!! If you are confused, I suggest you read one of Prof. Walter Lewin's most excellent lecture supplements here: http://ocw.mit.edu/courses/physics/802electricityandmagnetismspring2002/lecturenotes/lecsup41.pdf
 one year ago

elica85Best ResponseYou've already chosen the best response.0
inductor acts like a piece of wire when connected to battery. i'm sorry, i didn't make it clear in the drawing, the battery disconnects from the circuit so now the inductor does not act as just a piece of wire. it keeps the current flowing for time t.
 one year ago

elica85Best ResponseYou've already chosen the best response.0
i don't understand how to get potential difference without any given values. V_R=IR and V_L=LdI/dt
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.1
even then it is a piece of wire
 one year ago

elica85Best ResponseYou've already chosen the best response.0
but there is potential difference...?
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.1
no no... you've got it all wrong. This is all a misconception. that is why I posted the link. Read carefully and find out for yourselves!!!
 one year ago

ramkrishnaBest ResponseYou've already chosen the best response.0
a current carrying loop has a net magnetic flux. and whenever there is change in magnetic flux the loop will oppose that. (Lenz's law)
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.1
all of you who think there is a "potential difference" between the ends of an inductor should seriously watch this video completely: http://ocw.mit.edu/courses/physics/802electricityandmagnetismspring2002/videolectures/lecture16electromagneticinduction/ PLEASE FOR THE SAKE OF CORRECT UNDERSTANDING
 one year ago

elica85Best ResponseYou've already chosen the best response.0
thank you i will be watching it soon but must study so i have no time right this moment. thx~
 one year ago
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