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\[\ln(5+c)=\sqrt{5-4} \text{ we want left limit equal to right limit} \]

\[\ln(5+c)=1 \]
You need to solve this

freckles is right

Seems awesome to me

:D
Thanks a lot!

awesome )

Well f(5)=lim x-> 5 f(x) in order for it to also be continuous at x=5

so what did you get for lim x-> 5 f(x) ?

Oh, it's 1, right? So... f(5) = 1 for f(x) to be continuous at x=5?

Yep yep.

Ahh, how silly of me, thanks :)