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## anonymous 4 years ago Trigonometric Identities question: http://d.pr/i/FsnP I got my answer to be 3/2 but the mark scheme says -3/2.

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1. .Sam.

$3\cos2 \beta+19\cos \beta+13=0$ $Use ~~~~\cos2\beta=2\cos^2\beta-1$ $3(2\cos^2\beta-1)+19\cos \beta+13=0$ $6\cos^2\beta-3+19\cos \beta+13=0$ $6\cos^2\beta+19\cos \beta+10=0$ $(2\cos \beta+5)(3\cos \beta+2)=0$ $\cos \beta=-5/2, \cos \beta =-2/3$

2. anonymous

Thanks. I made a silly mistake.

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