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estebananayaBest ResponseYou've already chosen the best response.0
its the effective value of the current, that means that the rms value supplies the same power as a dc source
 2 years ago

DyiliqBest ResponseYou've already chosen the best response.0
You can find it by using the same formula as for voltage on the current wave. In some circuits, they are parallel to one another, and for others they are out of phase, but at any rate, they use the same equation
 2 years ago

DyiliqBest ResponseYou've already chosen the best response.0
Vrms=\[Vp * {(\sqrt{2}) \over 2}\]
 2 years ago

MohithBest ResponseYou've already chosen the best response.0
Rms stands for Root Mean Square. It is a totally a mathematical concept and is used to find a non zero average for quantities that have both positive and negative values. It is defined as root of sum of square of all quantities divided by the no of quantities. In case of constantly varying values the "sum" can be converted to integration. Thus for any form of current waveform RMS can be found by using this concept. Using this concept for a current varying as a sinusoidal waveform, the rms value of current comes as\[I _{0}/\sqrt{2}\]
 2 years ago

DyiliqBest ResponseYou've already chosen the best response.0
I have a textbook here, sir, that disagrees with you in whole. RMS is meant to indicate the aount of DC voltage that would dissipate the same amout of heat as the AC voltage. This value is less than \[V_p or I_p\] \[(\sqrt{2})\over(2)\]=\[I_{rms}\]
 2 years ago

shahzadjalbaniBest ResponseYou've already chosen the best response.0
RMS value is root mean square value which is multiplied with an AC sinusoidal to provide the same heating effect as DC produces.
 2 years ago

sisiBest ResponseYou've already chosen the best response.0
\[\sqrt{ \int\limits_{0}^{T}1/T(i(t)^2)dt}\]
 2 years ago

ShashankYadavBest ResponseYou've already chosen the best response.0
RMS (Root mean square), it is that value of D.C current which produce the same heat, which is produced by the A.C current in the same circuit. \[Irms=Imax \div \sqrt{2}\]
 2 years ago

DyiliqBest ResponseYou've already chosen the best response.0
\[I_{rms}={I_{\max}\over \sqrt2}\]right? ....Right.
 2 years ago

DyiliqBest ResponseYou've already chosen the best response.0
How is this different from\[(I_{rms})*(\sqrt(2) \over \sqrt{2}\]?
 2 years ago
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