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.Sam. Group Title

In an AP, d=1.6, a=6 \[S_{n}=pn^2+qn \] Find p and q

  • 2 years ago
  • 2 years ago

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  1. .Sam. Group Title
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    @experimentX @lgbasallote @Callisto Try this? :)

    • 2 years ago
  2. Callisto Group Title
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    I'm going to give wrong answers :( T(n) = 6+1.6(n-1) S(n) = [6+ ( 6+1.6(n-1)) ] n/2 = (12+1.6n -1.6) n/2 = (1.6n^2 + 10.4n)/2 = 0.8n^2 + 5.2n p= 0.8, q=5.2

    • 2 years ago
  3. lgbasallote Group Title
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    a is first term right? A_n = 6 +(n-1)1.6 A_n = 6 + 1.6n - 1.6 A_n = 4.4 + 1.6n S_n = n(A_1 + A_n)/2 pn^2 + qn = n(6 + 4.4 + 1.6n)/2 n(pn + q) = n(10.4 + 1.6n)/2 pn + q = 5.2 + 0.8n

    • 2 years ago
  4. lgbasallote Group Title
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    lol i didnt know what to do with that...genius caLLISTO!

    • 2 years ago
  5. .Sam. Group Title
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    @Callisto is correct :D

    • 2 years ago
  6. Callisto Group Title
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    Oh... I must be dreaming :(....

    • 2 years ago
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