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How do I show the real roots in for this graph? http://d.pr/i/COS9
 one year ago
 one year ago
How do I show the real roots in for this graph? http://d.pr/i/COS9
 one year ago
 one year ago

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dpaIncBest ResponseYou've already chosen the best response.0
be truthful to yourself.
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
dw:1334914514106:dw This is my drawing.
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
Real roots means xaxis intercepts
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
So is it 2 and where line y= x+16 intercepts the x axis?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
adnanchowdhury, bad drawing, it should only touch the xaxis
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
and yes, it is 2 and 16
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
Are you sure? because when x=0, y=16?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
does not make a difference, you want y = 0
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
and y = 0. when x = 16
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
sorry, just read the question again, the roots are the solutions to the question, which means the intercepts between the 2 graphs: dw:1334914789804:dw
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
clearly one of the roots is at x = 0 and the only other root is where the line extends to meet the curve
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
okay, so there are 3 roots?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
(x2)^4 = x+16 so x^4 8x^3+24x^232x+16 = x16
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
16 cancels, and you can factor out x, so one solution is at x = 0
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
now, x^3 8x^2+24x32 = 0
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
this is a third order polynomial with one xintercept, so the solution to this equation, and x = 0, are the only 2 roots
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
and so how do i show this on the graph?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.1
dw:1334915153788:dw
 one year ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
oh i see. Thanks.
 one year ago
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