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adnanchowdhury
Group Title
How do I show the real roots in for this graph? http://d.pr/i/COS9
 2 years ago
 2 years ago
adnanchowdhury Group Title
How do I show the real roots in for this graph? http://d.pr/i/COS9
 2 years ago
 2 years ago

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dpaInc Group TitleBest ResponseYou've already chosen the best response.0
be truthful to yourself.
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
dw:1334914514106:dw This is my drawing.
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
Real roots means xaxis intercepts
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
So is it 2 and where line y= x+16 intercepts the x axis?
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
adnanchowdhury, bad drawing, it should only touch the xaxis
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
and yes, it is 2 and 16
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
Are you sure? because when x=0, y=16?
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
does not make a difference, you want y = 0
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
and y = 0. when x = 16
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
sorry, just read the question again, the roots are the solutions to the question, which means the intercepts between the 2 graphs: dw:1334914789804:dw
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
clearly one of the roots is at x = 0 and the only other root is where the line extends to meet the curve
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
okay, so there are 3 roots?
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
(x2)^4 = x+16 so x^4 8x^3+24x^232x+16 = x16
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
16 cancels, and you can factor out x, so one solution is at x = 0
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
now, x^3 8x^2+24x32 = 0
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
this is a third order polynomial with one xintercept, so the solution to this equation, and x = 0, are the only 2 roots
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
and so how do i show this on the graph?
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
dw:1334915153788:dw
 2 years ago

Lumenaire Group TitleBest ResponseYou've already chosen the best response.1
like that :)
 2 years ago

adnanchowdhury Group TitleBest ResponseYou've already chosen the best response.0
oh i see. Thanks.
 2 years ago
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