Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

nilankshi

  • 2 years ago

obtain all the zeroes of 3x^4+6x^2-2x^2-10x-5,if two zeroes are root5/3 and -root 5/3

  • This Question is Closed
  1. Lumenaire
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I assume you mean: 3x^4+6x^3-2x^2-10x-5

  2. lgbasallote
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the roots aree \(\large \sqrt{\frac{5}{3}}\) and \(\large -\sqrt{\frac{5}{3}}\) right? or is the root applied on 5 only?

  3. Lumenaire
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is there a square root sign at all? I understood that 5/3 and -5/3 are the roots

  4. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    divide the whole system by its two factors that are given (or try synthetic division) After two whole divisions by each factor, you 'll be left with a quadratic as the quotient, factorising which you'll get you the other two roots.

  5. lgbasallote
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    he/she said root 5/3 and root -5/3..she already said zeroes so i assume root->radical

  6. nilankshi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes that is right..

  7. nilankshi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    root is on both..

  8. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\mathbb{yes}\]

  9. Lumenaire
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and is it an x^3 in the equation?

  10. Lumenaire
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (6x^2) should be 6x^3

  11. nilankshi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes it is in equion

  12. lgbasallote
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \(\large x = \sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2 - 5 = 0\) as for the other zero... \(\large x = -\sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2 - 5 = 0\) so two of the factors would be (3x^2 - 5)^2

  13. lgbasallote
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    something doesnt feel right...

  14. nilankshi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yaa..

  15. lgbasallote
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm idk how to do this sorry... @apoorvk may know though

  16. nilankshi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its ok..

  17. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry, Trance. :) and Nilakshi. I 'll work on the solution now

  18. TranceNova
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks :) @Rohangrr if you want to talk about it, please make a new question.

  19. phi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 4

    I would multiply out \[ (x-\sqrt{5/3})(x+\sqrt{5/3}) = x^2-\frac{5}{3}\] we can write this as \(3x^2-5\) (why? see below) divide this into the original equation to get \(x^2+2x+1 \) now factor this to get the remaining roots. * we are looking for \((x^2-\frac{5}{3}) (x^2+2x+1) =0\) if we multiply both sides by 3 we get \( 3(x^2-\frac{5}{3})(x^2+2x+1) =0\) \( (3x^2-5) (x^2+2x+1)=0\)

  20. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hmm, I got so bored, Phi already posted it. :/ Good job, Phi

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.