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nilankshi
 3 years ago
obtain all the zeroes of 3x^4+6x^22x^210x5,if two zeroes are root5/3 and root 5/3
nilankshi
 3 years ago
obtain all the zeroes of 3x^4+6x^22x^210x5,if two zeroes are root5/3 and root 5/3

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Lumenaire
 3 years ago
Best ResponseYou've already chosen the best response.0I assume you mean: 3x^4+6x^32x^210x5

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2the roots aree \(\large \sqrt{\frac{5}{3}}\) and \(\large \sqrt{\frac{5}{3}}\) right? or is the root applied on 5 only?

Lumenaire
 3 years ago
Best ResponseYou've already chosen the best response.0is there a square root sign at all? I understood that 5/3 and 5/3 are the roots

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0divide the whole system by its two factors that are given (or try synthetic division) After two whole divisions by each factor, you 'll be left with a quadratic as the quotient, factorising which you'll get you the other two roots.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2he/she said root 5/3 and root 5/3..she already said zeroes so i assume root>radical

Lumenaire
 3 years ago
Best ResponseYou've already chosen the best response.0and is it an x^3 in the equation?

Lumenaire
 3 years ago
Best ResponseYou've already chosen the best response.0(6x^2) should be 6x^3

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2\(\large x = \sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2  5 = 0\) as for the other zero... \(\large x = \sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2  5 = 0\) so two of the factors would be (3x^2  5)^2

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2something doesnt feel right...

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2hmm idk how to do this sorry... @apoorvk may know though

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, Trance. :) and Nilakshi. I 'll work on the solution now

TranceNova
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks :) @Rohangrr if you want to talk about it, please make a new question.

phi
 3 years ago
Best ResponseYou've already chosen the best response.4I would multiply out \[ (x\sqrt{5/3})(x+\sqrt{5/3}) = x^2\frac{5}{3}\] we can write this as \(3x^25\) (why? see below) divide this into the original equation to get \(x^2+2x+1 \) now factor this to get the remaining roots. * we are looking for \((x^2\frac{5}{3}) (x^2+2x+1) =0\) if we multiply both sides by 3 we get \( 3(x^2\frac{5}{3})(x^2+2x+1) =0\) \( (3x^25) (x^2+2x+1)=0\)

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm, I got so bored, Phi already posted it. :/ Good job, Phi
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