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obtain all the zeroes of 3x^4+6x^22x^210x5,if two zeroes are root5/3 and root 5/3
 one year ago
 one year ago
obtain all the zeroes of 3x^4+6x^22x^210x5,if two zeroes are root5/3 and root 5/3
 one year ago
 one year ago

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LumenaireBest ResponseYou've already chosen the best response.0
I assume you mean: 3x^4+6x^32x^210x5
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
the roots aree \(\large \sqrt{\frac{5}{3}}\) and \(\large \sqrt{\frac{5}{3}}\) right? or is the root applied on 5 only?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.0
is there a square root sign at all? I understood that 5/3 and 5/3 are the roots
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
divide the whole system by its two factors that are given (or try synthetic division) After two whole divisions by each factor, you 'll be left with a quadratic as the quotient, factorising which you'll get you the other two roots.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
he/she said root 5/3 and root 5/3..she already said zeroes so i assume root>radical
 one year ago

LumenaireBest ResponseYou've already chosen the best response.0
and is it an x^3 in the equation?
 one year ago

LumenaireBest ResponseYou've already chosen the best response.0
(6x^2) should be 6x^3
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
\(\large x = \sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2  5 = 0\) as for the other zero... \(\large x = \sqrt{\frac{5}{3}}\) \(\large x^2 = \frac{5}{3}\) \(\large 3x^2 = 5\) \(\large 3x^2  5 = 0\) so two of the factors would be (3x^2  5)^2
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
something doesnt feel right...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
hmm idk how to do this sorry... @apoorvk may know though
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
Sorry, Trance. :) and Nilakshi. I 'll work on the solution now
 one year ago

TranceNovaBest ResponseYou've already chosen the best response.0
Thanks :) @Rohangrr if you want to talk about it, please make a new question.
 one year ago

phiBest ResponseYou've already chosen the best response.4
I would multiply out \[ (x\sqrt{5/3})(x+\sqrt{5/3}) = x^2\frac{5}{3}\] we can write this as \(3x^25\) (why? see below) divide this into the original equation to get \(x^2+2x+1 \) now factor this to get the remaining roots. * we are looking for \((x^2\frac{5}{3}) (x^2+2x+1) =0\) if we multiply both sides by 3 we get \( 3(x^2\frac{5}{3})(x^2+2x+1) =0\) \( (3x^25) (x^2+2x+1)=0\)
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
Hmm, I got so bored, Phi already posted it. :/ Good job, Phi
 one year ago
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