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Naomi22
What is the relationship of the angle of release and the trajectory of a projectile?
|dw:1334929684012:dw| is that what you mean??
if 45 degr max x gets max
If the object is projected with velocity V at an angle @ then, Horizontal component of velocity = V.cos@ and vertical component = V.sin@ At an instant 't', X = V.cos@*t Y = V.sin@*t - g*t^2 /2 Now, you can eliminate parameter 't' by substituting t = X/V.cos@ in second equation You will get equation of trajectory, equation relating @ and trajectory. Hope it helps !!
Thanks I really appreciate your answers.