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Naomi22 Group Title

What is the relationship of the angle of release and the trajectory of a projectile?

  • 2 years ago
  • 2 years ago

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  1. mos1635 Group Title
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    |dw:1334929684012:dw| is that what you mean??

    • 2 years ago
  2. sanjeeth Group Title
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    ya

    • 2 years ago
  3. mos1635 Group Title
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    if 45 degr max x gets max

    • 2 years ago
  4. shubham Group Title
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    If the object is projected with velocity V at an angle @ then, Horizontal component of velocity = V.cos@ and vertical component = V.sin@ At an instant 't', X = V.cos@*t Y = V.sin@*t - g*t^2 /2 Now, you can eliminate parameter 't' by substituting t = X/V.cos@ in second equation You will get equation of trajectory, equation relating @ and trajectory. Hope it helps !!

    • 2 years ago
  5. Naomi22 Group Title
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    Thanks I really appreciate your answers.

    • 2 years ago
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