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@Akshay_Budhkar , we can find that by simply using area of a square? right?

yes 8^2=64 =D

Perfect. ;D

exactly..

aha the y-axis is degrees / hour! not degrees!

Lol.

It's not easy. haha

u already did :P i am trying

haha.

ok i get it

lets start with A

are you clear with A ?

@Akshay_Budhkar idk but i feel like we have to find some derivatives?

Yes I understand what you said with A.

@saifoo.khan yes

*d=-8t^2-8

Thank you so much I understood that! Would you be able to help me with question 4 by chance?

ok lemme see, is it one unit for each square right?

That is what I understand.

ok lets start with the simplest
C. f(3) = 5 any doubt?

Yes, thats what I see.

Okay, that makes sense to me.

is it unclear?

So you think D would be =-2 to 4?

the area under the graph , from -2 to 4

Okay

Can you solve it?
For the other questions i would personally plot a graph for f'(x)

f"(x)=d/dx*f'(x)

Sorry I am just thinking. Okay, Thanks.

Okay, thank you so much for your help!