Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Can some help with question 2 and 4? I will post document.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

A] Propose a value for the following definite integral and give an interpretation for the result : is nothing but the area under the curve from the values x=6 to x=8
@Akshay_Budhkar , we can find that by simply using area of a square? right?
yes 8^2=64 =D

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Perfect. ;D
exactly..
aha the y-axis is degrees / hour! not degrees!
Lol.
It's not easy. haha
u already did :P i am trying
haha.
Amistre64 was helping me on this question but I was still lost so I was hoping if someone else also explained it maybe I would understand.
ok i get it
lets start with A
are you clear with A ?
@Akshay_Budhkar idk but i feel like we have to find some derivatives?
Yes I understand what you said with A.
@saifoo.khan yes
ok now let degrees be d and time be t so on y axis we have d/t and x axis we have t Now till x= 1 it is a straight line, with a slope -8 and intercept -8 so the equation is y=mx+c that is y=-8x-8 that is d/t=-8t-8 d=-8t^2=8t
*d=-8t^2-8
Now for minima or maxima the first derivative of the function is o therefore\[{d(d) \over dt }=0=-16t-8 \therefore t= 1/2\]
Now to find if it is a minima or a maxima we take the second derivative. if it is negative it is a maxima if positive minima ( mostly i maybe mixing them ) so in this case it is -16 which is negative. therefore it is a maxima at 1/2
Thank you so much I understood that! Would you be able to help me with question 4 by chance?
ok lemme see, is it one unit for each square right?
That is what I understand.
ok lets start with the simplest C. f(3) = 5 any doubt?
Yes, thats what I see.
ok now A. f'(-2) Now i believe that at a given point \[f'(x)={dy \over dx} = { y \over x}\] if we estimate. so f'(-2) =-2/-2 = 1
Okay, that makes sense to me.
for D its the same logic, area under the curve. i believe you can assume the graph to be a triangle and calculate the area
is it unclear?
So you think D would be =-2 to 4?
the area under the graph , from -2 to 4
Okay
Can you solve it? For the other questions i would personally plot a graph for f'(x)
f"(x)=d/dx*f'(x)
yes i know. Now to plot the graph u must know that it is zero at minima and maxima, and u can fidn approximate values by using the approximation of y/x, and plot the graph of f'
then after i get the graph, f"' will be obtained by using y/x again and the last one by area under curve in that graph
Sorry I am just thinking. Okay, Thanks.
yup give it a thought, and lemme know if ustuck =D and u can tag me in some other question if u get some similar doubt =D
Okay, thank you so much for your help!

Not the answer you are looking for?

Search for more explanations.

Ask your own question