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tburn
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Can some help with question 2 and 4? I will post document.
 2 years ago
 2 years ago
tburn Group Title
Can some help with question 2 and 4? I will post document.
 2 years ago
 2 years ago

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Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
A] Propose a value for the following definite integral and give an interpretation for the result : is nothing but the area under the curve from the values x=6 to x=8
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
@Akshay_Budhkar , we can find that by simply using area of a square? right?
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
yes 8^2=64 =D
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Perfect. ;D
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
exactly..
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
aha the yaxis is degrees / hour! not degrees!
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
It's not easy. haha
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
u already did :P i am trying
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Amistre64 was helping me on this question but I was still lost so I was hoping if someone else also explained it maybe I would understand.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
ok i get it
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
lets start with A
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
are you clear with A ?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
@Akshay_Budhkar idk but i feel like we have to find some derivatives?
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Yes I understand what you said with A.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
@saifoo.khan yes
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
ok now let degrees be d and time be t so on y axis we have d/t and x axis we have t Now till x= 1 it is a straight line, with a slope 8 and intercept 8 so the equation is y=mx+c that is y=8x8 that is d/t=8t8 d=8t^2=8t
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
*d=8t^28
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
Now for minima or maxima the first derivative of the function is o therefore\[{d(d) \over dt }=0=16t8 \therefore t= 1/2\]
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
Now to find if it is a minima or a maxima we take the second derivative. if it is negative it is a maxima if positive minima ( mostly i maybe mixing them ) so in this case it is 16 which is negative. therefore it is a maxima at 1/2
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much I understood that! Would you be able to help me with question 4 by chance?
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
ok lemme see, is it one unit for each square right?
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
That is what I understand.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
ok lets start with the simplest C. f(3) = 5 any doubt?
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Yes, thats what I see.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
ok now A. f'(2) Now i believe that at a given point \[f'(x)={dy \over dx} = { y \over x}\] if we estimate. so f'(2) =2/2 = 1
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Okay, that makes sense to me.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
for D its the same logic, area under the curve. i believe you can assume the graph to be a triangle and calculate the area
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
is it unclear?
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
So you think D would be =2 to 4?
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
the area under the graph , from 2 to 4
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
Can you solve it? For the other questions i would personally plot a graph for f'(x)
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
f"(x)=d/dx*f'(x)
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
yes i know. Now to plot the graph u must know that it is zero at minima and maxima, and u can fidn approximate values by using the approximation of y/x, and plot the graph of f'
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
then after i get the graph, f"' will be obtained by using y/x again and the last one by area under curve in that graph
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Sorry I am just thinking. Okay, Thanks.
 2 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.3
yup give it a thought, and lemme know if ustuck =D and u can tag me in some other question if u get some similar doubt =D
 2 years ago

tburn Group TitleBest ResponseYou've already chosen the best response.0
Okay, thank you so much for your help!
 2 years ago
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