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if she misses her first serve, her second serve goes in 90% of the time. whe this happens, she wins the point on her second serve 35% of the time. find the probability that venus wins a point when she is serving.
probability was never my strong point, but I could take a guess at this.
you guys have any ideas of how to go about solving this?
what i would do would be: \[.75*.80 + (1 - .75*.80)*.9*.35\] the first part being the probability of her winning her first serve and the second of her winning her second serve given a result of her first serve. again its been forever since I've done any probability
p(wp|Gs1)=80% p(wp|Gs2)=35% p(Gs1)=75% P(Gs2)=90%
is the periods in between multiplications symbols? @RaphaelFilgueiras
tihs is the probability of win a point if she gets first server
a player is allowed two serves each time in tennis. sorry i forgot to mention that.
the secons time Gs2
P(wp) is the probability to win a pint
the question just says find the P when she is serving. it doesnt when wether is first or second. what shoudl i do?
that formula take accounting the two cases,its impossible she gain a ponit without serving
have you played tennis before?
or know how the serving works?
oh ok. the problem also says draw a tree diagram. i will post here.
in tennis you have two attempts to get in a good serve with each serve. IF you miss the first one you move onto the second.
try mulitplying the circled numbers together, then the squared ones, then adding them together,.
ok, that makes alot more sense. thanks for help! really aprreciate it
i got 67.8%
So, i) She could either get her first serve in and get a point (0.75 * 0.80) ii) She could else get her first serve wrong, second serve right and point on her second serve ( 0.25 * 0.90 * 0.35) Sum up i) and ii) 0.6 + 0.079 That's 67.9% , same as what you got! So guess its right! :D