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ananaa

  • 4 years ago

find the solution for: log(3x-1)+log2=log4+log(x+2)

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  1. slaaibak
    • 4 years ago
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    Use this: log a + log b = log ab

  2. rulnick
    • 4 years ago
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    log(3x-1)-log(x+2) = log4 - log2 log((3x-1)/(x+2)) = log(4/2) (3x-1)/(x+2) = 2 3x-1=2x+4 x=5

  3. campbell_st
    • 4 years ago
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    simplify the logs 1st log(3x-1) + log 2 = log(2(3x -1) or log(6x - 2) log 4 + log( x + 2) = log(4(x+2) = log(4x + 8) now equate both sides and solve for x 6x - 2 = 4x + 8 2x = 10 x = 5

  4. ananaa
    • 4 years ago
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    Thanks:) would you solve log(4x-1)=log(x+1)+log2 the same way

  5. campbell_st
    • 4 years ago
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    log(x+1) + log 2 = log(2(x+1) or log(2x + 2) so log(4x -1) = log(2x +2) equate and solve for x 4x -1 = 2x + 2 2x = 3 x = 3/2

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