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ananaa
 3 years ago
find the solution for:
log(3x1)+log2=log4+log(x+2)
ananaa
 3 years ago
find the solution for: log(3x1)+log2=log4+log(x+2)

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slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Use this: log a + log b = log ab

rulnick
 3 years ago
Best ResponseYou've already chosen the best response.0log(3x1)log(x+2) = log4  log2 log((3x1)/(x+2)) = log(4/2) (3x1)/(x+2) = 2 3x1=2x+4 x=5

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2simplify the logs 1st log(3x1) + log 2 = log(2(3x 1) or log(6x  2) log 4 + log( x + 2) = log(4(x+2) = log(4x + 8) now equate both sides and solve for x 6x  2 = 4x + 8 2x = 10 x = 5

ananaa
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks:) would you solve log(4x1)=log(x+1)+log2 the same way

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2log(x+1) + log 2 = log(2(x+1) or log(2x + 2) so log(4x 1) = log(2x +2) equate and solve for x 4x 1 = 2x + 2 2x = 3 x = 3/2
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