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morgansalmon
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Jeremy is building a large deck for a community center. The deck is shaped as a rectangle. The width of the deck is 29 feet. The perimeter of the deck is to be at least 134 feet.
 2 years ago
 2 years ago
morgansalmon Group Title
Jeremy is building a large deck for a community center. The deck is shaped as a rectangle. The width of the deck is 29 feet. The perimeter of the deck is to be at least 134 feet.
 2 years ago
 2 years ago

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kumar2006 Group TitleBest ResponseYou've already chosen the best response.0
L=length W=width P=perimeter P = 2L+2W So, P = 2L+2*29 > 134 The answer for A is 2L+58>134 To find the length, solve for L. 2L+58>134 2L>76 L>38 So, all possible values for the length of the deck, with a width of 29, can take on all values that are greater than 38.
 2 years ago

kumar2006 Group TitleBest ResponseYou've already chosen the best response.0
Start with the equation of a perimeter for a rectangle P = 2( l x w ) Fill in the known values 134 = 2 ( l x 29 ) Now the deck is supposed to be at least 134 ft, so create an inequality 134 < 2( l x 29
 2 years ago
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