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morgansalmon Group Title

Jeremy is building a large deck for a community center. The deck is shaped as a rectangle. The width of the deck is 29 feet. The perimeter of the deck is to be at least 134 feet.

  • 2 years ago
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  1. kumar2006 Group Title
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    L=length W=width P=perimeter P = 2L+2W So, P = 2L+2*29 > 134 The answer for A is 2L+58>134 To find the length, solve for L. 2L+58>134 2L>76 L>38 So, all possible values for the length of the deck, with a width of 29, can take on all values that are greater than 38.

    • 2 years ago
  2. kumar2006 Group Title
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    Start with the equation of a perimeter for a rectangle P = 2( l x w ) Fill in the known values 134 = 2 ( l x 29 ) Now the deck is supposed to be at least 134 ft, so create an inequality 134 < 2( l x 29

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