anonymous
  • anonymous
p^2x^2+2px+1=0 solve using the quadratic formula
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1335056613189:dw| what is a? or how do you solve for a here?
anonymous
  • anonymous
Assuming p is a real number, p^2 = a, 2p = b and c = 1, because they are all constants.
anonymous
  • anonymous
so what is the rest...? do i just ignore it? the xs?

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anonymous
  • anonymous
x is the x in the quadratic equation. It will become:\[x = (-2p \pm \sqrt{(2p)^{2} - 4p^{2}})/(2p^{2})\]
anonymous
  • anonymous
Actually, it's just (px)^2 + 2px + 1 = 0. We can just easily factor this especially since C here only has (1)(1) as its factors. (px + 1)(px + 1). :)
anonymous
  • anonymous
a quadratic equation can be written in the form:\[ax^2 + bx + c = 0\]then we get\[a = p^2\]\[b = 2p\]\[c = 1\]after that you just need to plug them to the quadratic formula\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
anonymous
  • anonymous
@imagreencat Indeed, that's easier to solve :-)
anonymous
  • anonymous
thanks everyone :)
anonymous
  • anonymous
You're welcome!

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