Simplify: (Points : 1) 3

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Simplify: (Points : 1) 3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\text{Let} \space \sqrt{2} = x \space \text{then} \space 6\sqrt{2} - 3\sqrt{2} = 6x - 3x = 3x = 3\sqrt{2}\]
Basically, you are just going to combine like terms. And when one term has a sqrt(2), and there's a value before it, we can take 3sqrt(2) + 2sqrt(2) to be equal to 5sqrt(2). It's like saying 3 cows + 2 cows = 5 cows. the sqrt(2) is like the label of each term. Actually, like what Hero said above. Now, you may be confused with the second and third numbers because they contain two labels now. Don't mix them, because sqrt(y) is not equal to the sqrt(x) of the sqrt(z). These are three different labels. Just leave them that way. Like the expressing 3x + 2y = 5z is left that way.

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I have no idea what either of you said...
When you add or subtract the terms with root, the best way is factorize the root out!
Do you understand my explanation?
For example: 6√2 - 3√2 = ( 6 -3 ) *√2 = 3 √2
Of course, only the terms have the same root can be factored!
Not a clu what that means.
6√2 - 3√2 Which part do you see the same?
I hope @BazBendell isn't a first grader trying to understand 7th grade work.
@BazBendell would you prove that Hero is completely wrong ;)
The only way he could prove me wrong is by understanding the material somehow ;)

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