anonymous
  • anonymous
Simplify: (Points : 1) 3
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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Hero
  • Hero
\[\text{Let} \space \sqrt{2} = x \space \text{then} \space 6\sqrt{2} - 3\sqrt{2} = 6x - 3x = 3x = 3\sqrt{2}\]
anonymous
  • anonymous
Basically, you are just going to combine like terms. And when one term has a sqrt(2), and there's a value before it, we can take 3sqrt(2) + 2sqrt(2) to be equal to 5sqrt(2). It's like saying 3 cows + 2 cows = 5 cows. the sqrt(2) is like the label of each term. Actually, like what Hero said above. Now, you may be confused with the second and third numbers because they contain two labels now. Don't mix them, because sqrt(y) is not equal to the sqrt(x) of the sqrt(z). These are three different labels. Just leave them that way. Like the expressing 3x + 2y = 5z is left that way.

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anonymous
  • anonymous
Do you still need help?
anonymous
  • anonymous
I have no idea what either of you said...
anonymous
  • anonymous
When you add or subtract the terms with root, the best way is factorize the root out!
anonymous
  • anonymous
Do you understand my explanation?
anonymous
  • anonymous
For example: 6√2 - 3√2 = ( 6 -3 ) *√2 = 3 √2
anonymous
  • anonymous
Of course, only the terms have the same root can be factored!
anonymous
  • anonymous
Not a clu what that means.
anonymous
  • anonymous
6√2 - 3√2 Which part do you see the same?
Hero
  • Hero
I hope @BazBendell isn't a first grader trying to understand 7th grade work.
anonymous
  • anonymous
@BazBendell would you prove that Hero is completely wrong ;)
Hero
  • Hero
The only way he could prove me wrong is by understanding the material somehow ;)

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