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BazBendell Group Title

Simplify: (Points : 1) 3

  • 2 years ago
  • 2 years ago

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  1. BazBendell Group Title
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    • 2 years ago
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  2. Hero Group Title
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    \[\text{Let} \space \sqrt{2} = x \space \text{then} \space 6\sqrt{2} - 3\sqrt{2} = 6x - 3x = 3x = 3\sqrt{2}\]

    • 2 years ago
  3. imagreencat Group Title
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    Basically, you are just going to combine like terms. And when one term has a sqrt(2), and there's a value before it, we can take 3sqrt(2) + 2sqrt(2) to be equal to 5sqrt(2). It's like saying 3 cows + 2 cows = 5 cows. the sqrt(2) is like the label of each term. Actually, like what Hero said above. Now, you may be confused with the second and third numbers because they contain two labels now. Don't mix them, because sqrt(y) is not equal to the sqrt(x) of the sqrt(z). These are three different labels. Just leave them that way. Like the expressing 3x + 2y = 5z is left that way.

    • 2 years ago
  4. Chlorophyll Group Title
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    Do you still need help?

    • 2 years ago
  5. BazBendell Group Title
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    I have no idea what either of you said...

    • 2 years ago
  6. Chlorophyll Group Title
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    When you add or subtract the terms with root, the best way is factorize the root out!

    • 2 years ago
  7. Chlorophyll Group Title
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    Do you understand my explanation?

    • 2 years ago
  8. Chlorophyll Group Title
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    For example: 6√2 - 3√2 = ( 6 -3 ) *√2 = 3 √2

    • 2 years ago
  9. Chlorophyll Group Title
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    Of course, only the terms have the same root can be factored!

    • 2 years ago
  10. BazBendell Group Title
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    Not a clu what that means.

    • 2 years ago
  11. Chlorophyll Group Title
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    6√2 - 3√2 Which part do you see the same?

    • 2 years ago
  12. Hero Group Title
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    I hope @BazBendell isn't a first grader trying to understand 7th grade work.

    • 2 years ago
  13. Chlorophyll Group Title
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    @BazBendell would you prove that Hero is completely wrong ;)

    • 2 years ago
  14. Hero Group Title
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    The only way he could prove me wrong is by understanding the material somehow ;)

    • 2 years ago
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spraguer (Moderator)
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