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lim x->o (1-cosx)/x sqrt

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This seems to be a bit weird sqrt of what?
it's the new way...

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Other answers:

LOL @myininaya I thought It was \[\LARGE \lim_{x\to 0}{1-\cos x \over \sqrt x}\]
the lower is x^2
\[\LARGE \lim_{x\to 0}{1- \cos x\over x^2}\] ?
yes yes
do you l'hospital?
i mean know?
yes. but the question say use limit rule. don't use l'opitall's rule
i've tried to use factorization. but can't get it
ok \[\lim_{x \rightarrow 0}\frac{1-\cos(x)}{x^2} \cdot \frac{1+\cos(x)}{1+\cos(x)}\] \[\lim_{x \rightarrow 0}\frac{1-\cos^2(x)}{x^2(1+\cos(x))}=\lim_{x \rightarrow 0}\frac{\sin^2(x)}{x^2(1+\cos(x))}\] need more help?
\[\lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{1}{1+\cos(x)}\]
the answer should be?
so you got this right ?
actually no. what technique is this?
you wanted to use algebra and limit laws...
do you have any questions with the steps i performed?
is the ans 1/2?
you're supposed to know this rule: \[ \lim_{x\to0}{\sin x\over x}= ?\] what should be instead of "?"
so there's nothing to get confused of :) .. @myininaya solved it, you just had to substitute :)
thank you

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