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anonymous
 4 years ago
lim x>o (1cosx)/x sqrt
anonymous
 4 years ago
lim x>o (1cosx)/x sqrt

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2This seems to be a bit weird sqrt of what?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0LOL @myininaya I thought It was \[\LARGE \lim_{x\to 0}{1\cos x \over \sqrt x}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE \lim_{x\to 0}{1 \cos x\over x^2}\] ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. but the question say use limit rule. don't use l'opitall's rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i've tried to use factorization. but can't get it

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2ok \[\lim_{x \rightarrow 0}\frac{1\cos(x)}{x^2} \cdot \frac{1+\cos(x)}{1+\cos(x)}\] \[\lim_{x \rightarrow 0}\frac{1\cos^2(x)}{x^2(1+\cos(x))}=\lim_{x \rightarrow 0}\frac{\sin^2(x)}{x^2(1+\cos(x))}\] need more help?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[\lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{1}{1+\cos(x)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer should be?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2so you got this right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually no. what technique is this?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2you wanted to use algebra and limit laws...

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2do you have any questions with the steps i performed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you're supposed to know this rule: \[ \lim_{x\to0}{\sin x\over x}= ?\] what should be instead of "?"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so there's nothing to get confused of :) .. @myininaya solved it, you just had to substitute :)
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