Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.2
This seems to be a bit weird sqrt of what?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
it's the new way...
 2 years ago

Kreshnik Group TitleBest ResponseYou've already chosen the best response.1
LOL @myininaya I thought It was \[\LARGE \lim_{x\to 0}{1\cos x \over \sqrt x}\]
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
the lower is x^2
 2 years ago

Kreshnik Group TitleBest ResponseYou've already chosen the best response.1
\[\LARGE \lim_{x\to 0}{1 \cos x\over x^2}\] ?
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
yes yes
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
do you l'hospital?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
i mean know?
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
yes. but the question say use limit rule. don't use l'opitall's rule
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
i've tried to use factorization. but can't get it
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
ok \[\lim_{x \rightarrow 0}\frac{1\cos(x)}{x^2} \cdot \frac{1+\cos(x)}{1+\cos(x)}\] \[\lim_{x \rightarrow 0}\frac{1\cos^2(x)}{x^2(1+\cos(x))}=\lim_{x \rightarrow 0}\frac{\sin^2(x)}{x^2(1+\cos(x))}\] need more help?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
\[\lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{1}{1+\cos(x)}\]
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
the answer should be?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
so you got this right ?
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
actually no. what technique is this?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
you wanted to use algebra and limit laws...
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
do you have any questions with the steps i performed?
 2 years ago

niki Group TitleBest ResponseYou've already chosen the best response.0
is the ans 1/2?
 2 years ago

Kreshnik Group TitleBest ResponseYou've already chosen the best response.1
you're supposed to know this rule: \[ \lim_{x\to0}{\sin x\over x}= ?\] what should be instead of "?"
 2 years ago

Kreshnik Group TitleBest ResponseYou've already chosen the best response.1
so there's nothing to get confused of :) .. @myininaya solved it, you just had to substitute :)
 2 years ago

najwaischua Group TitleBest ResponseYou've already chosen the best response.0
thank you
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.