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najwaischua Group Title

lim x->o (1-cosx)/x sqrt

  • 2 years ago
  • 2 years ago

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  1. myininaya Group Title
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    This seems to be a bit weird sqrt of what?

    • 2 years ago
  2. dpaInc Group Title
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    it's the new way...

    • 2 years ago
  3. FoolForMath Group Title
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    lol

    • 2 years ago
  4. Kreshnik Group Title
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    LOL @myininaya I thought It was \[\LARGE \lim_{x\to 0}{1-\cos x \over \sqrt x}\]

    • 2 years ago
  5. najwaischua Group Title
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    the lower is x^2

    • 2 years ago
  6. Kreshnik Group Title
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    \[\LARGE \lim_{x\to 0}{1- \cos x\over x^2}\] ?

    • 2 years ago
  7. najwaischua Group Title
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    yes yes

    • 2 years ago
  8. myininaya Group Title
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    do you l'hospital?

    • 2 years ago
  9. myininaya Group Title
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    i mean know?

    • 2 years ago
  10. najwaischua Group Title
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    yes. but the question say use limit rule. don't use l'opitall's rule

    • 2 years ago
  11. najwaischua Group Title
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    i've tried to use factorization. but can't get it

    • 2 years ago
  12. myininaya Group Title
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    ok \[\lim_{x \rightarrow 0}\frac{1-\cos(x)}{x^2} \cdot \frac{1+\cos(x)}{1+\cos(x)}\] \[\lim_{x \rightarrow 0}\frac{1-\cos^2(x)}{x^2(1+\cos(x))}=\lim_{x \rightarrow 0}\frac{\sin^2(x)}{x^2(1+\cos(x))}\] need more help?

    • 2 years ago
  13. myininaya Group Title
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    \[\lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{\sin(x)}{x} \cdot \lim_{x \rightarrow 0}\frac{1}{1+\cos(x)}\]

    • 2 years ago
  14. najwaischua Group Title
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    the answer should be?

    • 2 years ago
  15. myininaya Group Title
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    so you got this right ?

    • 2 years ago
  16. najwaischua Group Title
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    actually no. what technique is this?

    • 2 years ago
  17. myininaya Group Title
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    you wanted to use algebra and limit laws...

    • 2 years ago
  18. myininaya Group Title
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    do you have any questions with the steps i performed?

    • 2 years ago
  19. niki Group Title
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    is the ans 1/2?

    • 2 years ago
  20. Kreshnik Group Title
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    you're supposed to know this rule: \[ \lim_{x\to0}{\sin x\over x}= ?\] what should be instead of "?"

    • 2 years ago
  21. najwaischua Group Title
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    1

    • 2 years ago
  22. Kreshnik Group Title
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    so there's nothing to get confused of :) .. @myininaya solved it, you just had to substitute :)

    • 2 years ago
  23. najwaischua Group Title
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    thank you

    • 2 years ago
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