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anonymous
 4 years ago
y=e^e^x
find y'
anonymous
 4 years ago
y=e^e^x find y'

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y' = u' e^u = e^x * e^(e^x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u go through the steps? i dont get it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The formula: y' = u' e^u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then just plug it into the formula :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mind going thru the steps?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In differentiating a function that contains another function (or a series of functions for some), you apply the chain rule. Actually, you perform the chain rule when you differentiate and differentiate the different layers of functions until you reach a point when you are differentiating the most basic function x and you just get 1. To get the y' of e^e^x, we should note that the first layer is e^x where x here is e^x. The deriv of e^x = e^x, so the deriv of the first layer is e^x, but since x here is e^x, we make it e^(e^x). Now for the second layer, it's just e^x where x here is still x. So the deriv of the second layer is e^x where x is x. Now for the third layer, the function is just x, and its deriv is just 1. This is where we stop. Deriv of first layer: e^(e^x) Deriv of second layer: e^x Derive of third layer: 1 (stopped here) Then we just multiply everything, as this is what the chain rule states. So the derivative of the e^(e^x) = (e^(e^x))(e^x)(1) or simply (e^(e^x))(e^x).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did u get the second layer as e^x as?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because usually it is just e^x, right? That's the most basic form of that function. In this case, however, e was raised to another e^x, which is another function in itself. That's the second layer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then what is the first layer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The first layer is e^(e^x) as a whole. The second layer is the e^x inside the first layer (the power).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is it clear already? :)
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