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Is there enough information given in this problem? My initial impression is no.

looks binomial

but that part doesn't give you any information

each box is being tested...the box is either good or bad...the probability it is bad is 20%

Of course without replacement!

20% 400 = 80

you could use a normal approximation

I'm all about the normal approximation today ;)

Tell me more, Zarkon. How could we determine the SD?

haha...normal approximation today...

brb

you don't...you are looking at all the boxes...and checking each one once.

all you need is independence between boxes

Thanks a lot!! :D

oh yes zarkon, in this case, they are all indepent. Thanks!! :D

independent*

Mean: 80
SD: sqrt(400*0.2*(.8)) = 8
90 is a z-score of 1.25

|dw:1335139433649:dw|

most texts want n(1-p) and np to be larger than 5

i mean 89.5

yea...the CLT again like the previous one. haha... thanks so much!