## Mcurtis71 Group Title The distance between two charged objects is doubled. What happens to the electrostatic force between the two? 2 years ago 2 years ago

• This Question is Open
1. RaphaelFilgueiras Group Title

|dw:1335141437944:dw|

2. .Sam. Group Title

$F=k\frac{q_{1}q_{2}}{r^2}$ So if double the distance, $F=k\frac{q_{1}q_{2}}{2^2}$ $F=k\frac{q_{1}q_{2}}{4}$ Force is 4 times as low