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Mcurtis71
The distance between two charged objects is doubled. What happens to the electrostatic force between the two?
|dw:1335141437944:dw|
\[F=k\frac{q_{1}q_{2}}{r^2}\] So if double the distance, \[F=k\frac{q_{1}q_{2}}{2^2}\] \[F=k\frac{q_{1}q_{2}}{4}\] Force is 4 times as low
The electrostatic force would decrease by (1/(2^2)) or 1/4 of the original force.