## anonymous 4 years ago The distance between two charged objects is doubled. What happens to the electrostatic force between the two?

• This Question is Open
1. anonymous

|dw:1335141437944:dw|

2. .Sam.

$F=k\frac{q_{1}q_{2}}{r^2}$ So if double the distance, $F=k\frac{q_{1}q_{2}}{2^2}$ $F=k\frac{q_{1}q_{2}}{4}$ Force is 4 times as low

3. anonymous

The electrostatic force would decrease by (1/(2^2)) or 1/4 of the original force.