## Mcurtis71 The distance between two charged objects is doubled. What happens to the electrostatic force between the two? one year ago one year ago

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1. RaphaelFilgueiras

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2. .Sam.

$F=k\frac{q_{1}q_{2}}{r^2}$ So if double the distance, $F=k\frac{q_{1}q_{2}}{2^2}$ $F=k\frac{q_{1}q_{2}}{4}$ Force is 4 times as low