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perfectionist

  • 2 years ago

calling all word problem lovers! Sam has $0.93 in a total of nine coins. She does not have a half dollar. How many of each coin does she have? Pennies, nickels, dimes, quarters

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  1. perfectionist
    • 2 years ago
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    keep in mind that we can use two quarters or five dimes because Sam does NOT have $0.50

  2. echec
    • 2 years ago
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    She must have 3 pennies since there is no other way to represent $.01. This leaves 6 coins to make $.90. If we use two quarters as well, we have accounted for $.53, which leaves us with $.40 to account for. For this we can use four times. Her coins are 3 pennies, 4 dimes, and 2 quarters. 3 + 4 + 2 = 9 coins .03 + .40 + .50 = .93

  3. perfectionist
    • 2 years ago
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    Sam does NOT have $0.50

  4. echec
    • 2 years ago
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    A half dollar is another kind of coin. Are you sure the problem is just not ruling out that sort of coin as an option?

  5. perfectionist
    • 2 years ago
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    it is? really?

  6. echec
    • 2 years ago
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    Mmhm. Don't see them a lot these days, though. I'm not sure of any other way to come up with her coinage.

  7. perfectionist
    • 2 years ago
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    okay. thank you!!!!!

  8. perfectionist
    • 2 years ago
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    wait, how many nickel would be used though?

  9. LagrangeSon678
    • 2 years ago
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    lol, 50 cent coin, can we also use sacajawea dollars

  10. echec
    • 2 years ago
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    We don't need to use any nickels. We would have to use at least ten coins for that (3 pennies, 2 nickels, 3 dimes, 2 quarters, because 2 nickels replaces one dime).

  11. perfectionist
    • 2 years ago
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    okay thanks again

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