## Algebra1Flunk What is the domain of the function y=3(sqrt[6x+42] 2 years ago 2 years ago

1. estudier

Whatever you define it to be...

2. Algebra1Flunk

$y = 3\sqrt{6+42}$

3. TomLikesPhysics

If you do not allow i (sqrt of -1) than it should be: $6x+42\ge0$$6x \ge-42$$x \ge-42/6$$x \in [-42/6 ; \infty [$