## anonymous 4 years ago . Evaluate: t^-ca^ca, where c = 3, a = 2, and t = -4

1. anonymous

just substitute $\LARGE t^{-c}\cdot a^c\cdot a$ $\LARGE (-4)^{-3}\cdot 2^3\cdot 2$ $\LARGE \left(\frac{1}{-4}\right)^{3}\cdot 16$ Continue... :)

2. anonymous

the ^c is suppose to be with the (a) that you multiplied with at the end

3. anonymous

well.. I'm confused, O_O you should have used parentheses ... is it $\Huge t^{-ca^{ca}}$ can you draw it ? :(

4. anonymous

|dw:1335207292275:dw|

5. anonymous

ok... |dw:1335207492157:dw|

6. anonymous

you got it :)