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smartgirl101

  • 4 years ago

. Evaluate: t^-ca^ca, where c = 3, a = 2, and t = -4

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  1. Kreshnik
    • 4 years ago
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    just substitute \[\LARGE t^{-c}\cdot a^c\cdot a\] \[\LARGE (-4)^{-3}\cdot 2^3\cdot 2\] \[\LARGE \left(\frac{1}{-4}\right)^{3}\cdot 16\] Continue... :)

  2. smartgirl101
    • 4 years ago
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    the ^c is suppose to be with the (a) that you multiplied with at the end

  3. Kreshnik
    • 4 years ago
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    well.. I'm confused, O_O you should have used parentheses ... is it \[\Huge t^{-ca^{ca}}\] can you draw it ? :(

  4. smartgirl101
    • 4 years ago
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    |dw:1335207292275:dw|

  5. Kreshnik
    • 4 years ago
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    ok... |dw:1335207492157:dw|

  6. smartgirl101
    • 4 years ago
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    you got it :)

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