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need_help!

  • 4 years ago

I would really appreciate if someone would actually solve this for me and see if my answer is correct. Thanks! Find the minimum value of the expression C = 2x + 3y, where x and y are subject to the constraints 3y+4x>=18 3y+x>=9 x-1>=0 y>=0 I got 12?

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  1. hamza_b23
    • 4 years ago
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    you still need help in this?

  2. need_help!
    • 4 years ago
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    Yes :) I just need the answer though because I have already solved and just want to see if my answer is correct.

  3. bmp
    • 4 years ago
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    I got the same answer. I multiplied eq. 2 by -1 and add in eq.1. So I got x >= 3 and y >= 2. As we want the minimum, we plug in x = 3 and y = 2 and get C = 12.

  4. bmp
    • 4 years ago
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    That is, both x >= 3 and y >= 2 satisfy the other 2 constrains, so we are okay doing it.

  5. need_help!
    • 4 years ago
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    Did you graph?

  6. bmp
    • 4 years ago
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    Nope, solved the system analitically.

  7. need_help!
    • 4 years ago
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    Cool :) You can do it without graphing?

  8. bmp
    • 4 years ago
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    http://www.quickmath.com/webMathematica3/quickmath/graphs/inequalities/advanced.jsp#c=plot_advancedgraphinequalities&v1=3*y%2B4*x+%3E%3D+18&v2=3*y%2Bx+%3E%3D+9&v3=x-1+%3E%3D+0&v4=y+%3E%3D+0&v7=x&v8=y&v9=0&v10=15&v11=0&v12=15 Here is the intersection of the solutions to the inequalities. Minimum is point (3,2)

  9. need_help!
    • 4 years ago
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    Nice! Thanks a lot for your help =)

  10. bmp
    • 4 years ago
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    No problem, mate :-)

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