kumar2006
What is the solution of the system of equations 2x − 5y = 11 and
−2x + 3y = −9?
(1) (−3,−1) (3) (3,−1)
(2) (−1,3) (4) (3,1)
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kumar2006
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Show Work Please!!!
LagrangeSon678
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were gonna do this together okay, real simple,
first, we should add the first equation to the second equation okay:
2x − 5y = 11
−2x + 3y = −9
+
---------------------
What do you get?
kumar2006
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-4x8y-2
kumar2006
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?
LagrangeSon678
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really? just look at this we have to add it like we would normally, it dosent matter if there are x and y's
(2x)+(-2x)=0
kumar2006
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Fine I got the first step
LagrangeSon678
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2x − 5y = 11
−2x + 3y = −9
+
---------------------
-2y=2
LagrangeSon678
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now can you find what y=?
kumar2006
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y = -1,3
kumar2006
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?
LagrangeSon678
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what? how did you get y=-1,3, from -2y=2, you have to solve for y
kumar2006
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I don't know how to solve for Y
LagrangeSon678
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if you have -2y=2, you dont know how to get y by ?itself
kumar2006
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Nope
LagrangeSon678
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okay if i have -2y=2, then what should be done is divide both sidezs by -2, that gives us y=-1
LagrangeSon678
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now, simply replace y=-1 into one of your orginal equation and get x
kumar2006
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What will be my final answer?
kumar2006
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?
LagrangeSon678
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you have to solve this :2x − 5(-1) = 11
kumar2006
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Thanks for everything but I rather get the answer
LagrangeSon678
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yeah, your gonna get far
kumar2006
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Thank You Sir.