Find the equation of the tangent to the curve at the given x value. y=sqrt(x^2+3),x=1

Find the equation of the tangent to the curve at the given x value. y=sqrt(x^2+3),x=1

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That was my final answer.

The correct answer os x-2y+3=0

find the derivative, replace x by 1 to get your slope, then use point slope formula

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