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|dw:1335261368315:dw|

I got up to this:|dw:1335261401688:dw|

|dw:1335261446849:dw|

Deriatives is f'(x) right? we're not doing that yet.

Methods we're using is substitution, factoring and the conjugate method.

dy/dx =lim (h-->0) (f(x+h)-f(x))/h
rather.

Yes. That's what I did.

But I can't go any further. |dw:1335262087563:dw| That's the furthest I got up to.

Expand your brackets and factor out a h.

The bottom one to? I was told not too.

Not sure - I'm not familiar with the long method, I just use the shortcut :)

Can you take derivatives? Must you use first principle to find it?

Derivatives is our next unit.

I can't isolate or factor out anything. I must had made a mistake beforehand I guess.

Anyone?

I guess not, but it's notm much like my work.

Oh shoot... I got some mistakes there! Wait

Once again :(

Oh my dear!!! The final answer should be -4/3 ... not -2 as I've written :S

Is your question \[\frac{3}{x^2-1}\] or \[\frac{3}{x^2+1}\]?

First one.

Maybe I should upload my work, and maybe you check for problems?

Sure!

IT's c.

Starting from c) at Scan001.

f(a) is not 1

f(a) is 3/ (a^2 -1)

but since x=2, I subbed in a=2 into that equation...

I thought the unknown to be m, and that h was still the variable withint the equation?

I've got an example here with me from my teacher.

What should I correct?

Sorry if I sound ignorant, but that's how I saw it in the example...the h is alone.

Do you mind uploading your example also?

It's good that you notice the difference :)

Yup :)

well, where do you need help with?
This is pretty long..

Maybe I should just leave this question. I tried this for over 2 hours by now.

First, what is the question?
\[\frac{1}{x-2} \]??
or
\[\frac{3}{x^{2}-1} \]??

Second one, whereas x=2.

Ok. Thanks for the attempt guys. I'll try other problems, and maybe this might make more sense.

wait..i will try and do it first..
can't you take the derivative which is easier?

Hmm..I might try it but it might take a while since i havent done these in a while...

No, I don't have anything important..i might be able to do it but not sure..lol

I have to review these anyway

^^That was mammoth. phew. Istim do you know how to differentiate using chain rule?

lol, i failed...do you remember how to do these apoor? my brain is failling me :(

No, I don't (Sorry, cleaning up house).

Hmm. so you want to do this by the first principle of finding derivatives okay.

I am just oh so selective in the method used. That be the end of me.

\[\large\frac{f(x+h)-f(x)}{h} =>\frac{\frac{3}{(x+h)^{2}-1}-\frac{3}{x^{2}-1}}{h} \]

right so far?

I have no idea.

should be the limit as h approaches zero, but, apart from that, correct. ^_^

I think that im doing it wrong..i dont think that its this complicated..

Perhaps you should just use quotient rule.

but it says derivatiive thing is not allowed..

\[\frac{3}{x^{2}-1} => 3(x^2-1)^{-1}\]
\[-3(x^2-1)^{-1}*2x \]
\[-6x(x^2-1)^{-1}\]
easier i suppose..