A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
5 pens are to be distributed among 4 children randomly. The probabilty that each child get altleast one pen is ??
@FoolForMath there are two formulas, which are:
\[(k1)C _{n1} \]
where k>Total no of nondistinguishable objects
n>total no of distinguishable receivers
and
\[(n+k1)C _{k} \]
Now can you tell me which formula to use in this case and why?
 2 years ago
5 pens are to be distributed among 4 children randomly. The probabilty that each child get altleast one pen is ?? @FoolForMath there are two formulas, which are: \[(k1)C _{n1} \] where k>Total no of nondistinguishable objects n>total no of distinguishable receivers and \[(n+k1)C _{k} \] Now can you tell me which formula to use in this case and why?

This Question is Closed

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.3I have already answered you (in that thread)

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry. By mistake I wrote the wrong name :(

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0No I am having doubt about which formula to use in which case??

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.3In this case. The "why" is explained well in the wike page.

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0I still don't get the difference between theorem 1 and theorem 2 in Stars and bars combinatorics. Can you please make it easier for me to differentiate them

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0Anybody willing to help??

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0@FoolForMath , sorry for troubling you once again, but I am still not getting the difference between theorem 1 and theorem 2 in Stars and bars combinatorics. Can you please make it easier for me to differentiate them ? Please???

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.3Sorry, right now I can't make things any easier for you.

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0Ok. No problem . Thanks for prompt reply @FoolForMath I will keep trying it myself :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.