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250 is the answer?

I'm not too sure of the answer, but 250 might be too big...

In distributing the boxes, is it possible to give 2 boxes to one student?

The order does matter. Remember that we are giving to 3 different students.

If YES then the answer is 250 if No then the answer should be 25.

By working, I mean the steps taken to get the answer.

Sure, \( S(5,3) \times \binom{3-1}{3-1} = 25 \)
Where S() is Stirling number of second kind.

Can't we do this in conventional way? hehe... No Stirling Number.

oh, nvm that, I'm possibly counting some combinations twice (if not more)

ohh wait...

ohh hehehe
(5P3*3P2)

5*4*3*3*2, hmm but m_charron2 got 3^2 there. WHY?

so, instead of 3^2, 3P2? but still (5*4*3)*6 > 25. How did foolformath get 25?