## grant330sims 3 years ago Part 1: Explain, in complete sentences, which method you would use to solve the following system of equations. (1 point) Part 2: Explain why you chose that method (1 point) Part 3: Provide the solution to the system. (2 points) x – 3y + 2z = –12 x + 2y + 3z = 6 2x – 3y – z = –2

1. Romero

What math are you taking?

2. grant330sims

Algebra 2

3. Romero

Yeah i don't know. I would say substitution.

4. grant330sims

well, I've got how to with two equations, just cant remember how to do three.

5. grant330sims

Having trouble, cuz if you can just tell me what do do, you dont have to give me the answer, I'll just figure it out

6. Bhavnazoon

such question is a system of linear equation for further mathematics....so we can reduce it to triangular system and use back substitution...........gaussian elimination would also be appropriate.....or use matrix format with row reduction appplication...actually i am doing an assignment on it

7. Bhavnazoon

the y is because we have 3 equations with 3 unknowns in it.so the given methods will be right

8. grant330sims

Bro, i have no idea what you just said..

9. Bhavnazoon

no bro but sis......i`ll give u the steps....you follow then do it....ok

10. aroub

Yeah I would say substitution too. Solving the first equation for x in terms of y and z yields, x=3y-2z-12. Substituting the value of x in the second and third equations yields a system of two equations in two unknowns: (3y-2z-12)+2y+3z=6 2(3y-2z-12)-3y-z=-2 => 3y-2z-12+2y+3z=6 6y-4z-24-3y-z=-2 => 5y+z=18 3y-5z=22 for z gives, z=-5y+18 substituting the value of z in the second equation gives: 3y-5(-5y+18)=22 3y+25y-90=22 28y=112 y=4 substituting the value of y in the first equation: 5(4)+z=18 20+z=18 z=-2 substituting the value of y and z in the value of x that we first got ^^ : x=3y-2z-12 x=3(4)-2(-2)-12 x=12+4-12 x=4 The solution set is: { (4,-2,4) }

11. grant330sims

Thank you soo much!

12. aroub

You're welcome!