anonymous
  • anonymous
find the 3rd sides mesurment DRAWING ATTACHED PLEASE HELP HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1335309476619:dw|
anonymous
  • anonymous
2
anonymous
  • anonymous
what is 2?

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anonymous
  • anonymous
there's no way to solve that...there must be a right angle or something
anonymous
  • anonymous
Are you trying to find the entire 3rd side of the triangle, or just the piece that is sticking above the circle?
anonymous
  • anonymous
the entire side.
anonymous
  • anonymous
|dw:1335310909396:dw|
anonymous
  • anonymous
Oh, okay - well that is much easier! We'll need to use the Pythagorean Theorem (a^2+b^2=c^2), plug in our numbers and find the missing side. First off, we need to know which side is the hypotenuse (the longest side of the triangle - straight across from a right angle).
anonymous
  • anonymous
Oh, wait - is this a right angle triangle? If it's not, you can't use the Pythagorean theorem.
anonymous
  • anonymous
it does not indicate anything about a right triangle
anonymous
  • anonymous
Okay - I completely understand what you're going through - I can't stand these type of problems that don't give you any extra info.! One sec . . . I'll see if I can figure this out.
anonymous
  • anonymous
Okay, I just figured it out . . .
anonymous
  • anonymous
Remember that "tangent" means that there's a right angle? Well, since the 13200 and the 4000 sides come together, and are tangent, we know that they create a right angle. So, we know that our mystery side is across from the right angle, making that our hypotenuse. So, we're going to plug 13200 in for a^2 and 4000 in for b^2 and see what we get. When we square each: a=174240000 and b=16000000 Now, we'll add them together: 190240000 Okay, now we're looking for c^2. Here's our equation so far: 190240000=c^2 All we need to do now, is take the square root of each side, and we find that c=13792.75172 Hope this helps!
anonymous
  • anonymous
I didn't round the answer - I'm not sure if you wanted it to be rounded.
anonymous
  • anonymous
THANK YOU!!!!!! you are the best :)
anonymous
  • anonymous
Ha, ha - you're very welcome! :) Good luck with your math!
anonymous
  • anonymous
i need a lot of help haha
anonymous
  • anonymous
:)
anonymous
  • anonymous
While I'm here, do you have any other problems that you need help with?
anonymous
  • anonymous
yes ill close this question and form another
anonymous
  • anonymous
I can't guarantee that I can answer them . . . but I'll try
anonymous
  • anonymous
Okay . . gotcha

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