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Okay . . . . do you know if the four angles in the middle are all right angles?
no i don't kno it doesn't indicate
Does the problem give any other info., or is what you put up all they give you?
that is all it gave :( i can't figure it out.
Okay, I understand . . . don't worry
do you understand it?
One sec . . . I'm looking up a rule for this
Well, I thought that you might need to use the property for adjacent angles (with alternate interior, exterior, etc.), but I'm not sure if that would work, here. As I'm a bit rusty with this, let me see if I can get someone else on here, to help you . . . .
that sounds familiar maybe you are correct
I'm asking someone to see if he can help you . . . 1 sec
Remember that the key thing here, is that triangles have 180 degrees
For angles in the same segment, angle at centre is twice angle at the circumference. Therefore, b = 2*53 = 106 b and c are angles on a straight line and their sum should be 180, therefore c = 180-106 c= 74 for a, again use the same property used to find b, therefore a is also 53 Another property is that the angle subtended by the diameter (in this case it is the line that passes through centre and touches a b and c) is always 90. Therefore (d+53)=90 Answers: a = 53 b = 106 c = 74 d = 37
Ah . . . thanks mubzz!