An internal explosion breaks an object initially at rest into two pieces, one of which has 1.6 times the mass of the other. If 5900J is released in the explosion, how much kinetic energy does each piece acquire?
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I know that one of the pieces has to exert kinetic energy that is 1.6 greater than the other, and that this amount plus that amount should equal 5900J. I'm unsure on how to obtain this answer though, I could just plug in random values until I come up with the answer, but that wouldn't be the best approach...
Explosion is an internal phenomenon, forces involved are internal and hence, form action-reaction force pair.
So, Forces on both the pieces ( A and B) are equal in magnitude, opposite in direction
i.e. Fa = Fb [ eq.1]
Here, you know the amount of energy released = 5900 J
So, 1/2* Ma* Va^2 + 1/2*Mb*Vb^2 = 5900 [ 4 variables ]
and you know relation b/w Ma and Mb [ Ma = 1.6*Mb]
You can also find a relation b/w Va and Vb using eq.1
Hope you know how to proceed further !!
first what energy does the bomb(with all parts intact )have?