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xEnOnn Group Title

Suppose there is a set of numbers: \(\{1,2,3,4,5\}\). I pick from the set of numbers 3 times. Each pick is independent. So there is replacement. Then, what is the probability of me getting a 1, a 3 and a 5? And, what is the probability of getting a 2, two 4s?

  • 2 years ago
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  1. myko Group Title
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    1/125 i would say

    • 2 years ago
  2. xEnOnn Group Title
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    This is for the first part or the second part of the question?

    • 2 years ago
  3. myko Group Title
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    same

    • 2 years ago
  4. myko Group Title
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    for bouth

    • 2 years ago
  5. xEnOnn Group Title
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    why would it be the same for the second one? There is a repeated number in there ie, two 4s.

    • 2 years ago
  6. myko Group Title
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    but there is a replacement. So it doesn't mater....

    • 2 years ago
  7. xEnOnn Group Title
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    Actually, I was thinking why wouldn't it be \(\frac{6}{125}\) for the first part, and \(\frac{3}{125}\) for the second part?

    • 2 years ago
  8. Zarkon Group Title
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    you should let people know if the order that you pick then numbers matters.

    • 2 years ago
  9. xEnOnn Group Title
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    @Zarkon I think the orders do matter in this case since it is a combination because I just need to get a 1, a 3, and a 5. Similarly for the other combination of 2,4,4.

    • 2 years ago
  10. Zarkon Group Title
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    if the order matter than myko's answer is correct. If the order does not matter then you are correct. whether the order matters or not depends on what the problem is asking for. to me, it sounds like the order does not matter...though the problem could have been written better

    • 2 years ago
  11. xEnOnn Group Title
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    oh yea you are right that the order does not matter. I said it wrongly in my previous comment. Thanks for the help! :)

    • 2 years ago
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