xEnOnn 3 years ago Suppose there is a set of numbers: $$\{1,2,3,4,5\}$$. I pick from the set of numbers 3 times. Each pick is independent. So there is replacement. Then, what is the probability of me getting a 1, a 3 and a 5? And, what is the probability of getting a 2, two 4s?

1. myko

1/125 i would say

2. xEnOnn

This is for the first part or the second part of the question?

3. myko

same

4. myko

for bouth

5. xEnOnn

why would it be the same for the second one? There is a repeated number in there ie, two 4s.

6. myko

but there is a replacement. So it doesn't mater....

7. xEnOnn

Actually, I was thinking why wouldn't it be $$\frac{6}{125}$$ for the first part, and $$\frac{3}{125}$$ for the second part?

8. Zarkon

you should let people know if the order that you pick then numbers matters.

9. xEnOnn

@Zarkon I think the orders do matter in this case since it is a combination because I just need to get a 1, a 3, and a 5. Similarly for the other combination of 2,4,4.

10. Zarkon

if the order matter than myko's answer is correct. If the order does not matter then you are correct. whether the order matters or not depends on what the problem is asking for. to me, it sounds like the order does not matter...though the problem could have been written better

11. xEnOnn

oh yea you are right that the order does not matter. I said it wrongly in my previous comment. Thanks for the help! :)