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TomLikesPhysics
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If I have a function: y=K*e^x is there a way to rewrite it as y=C*A^x where A does not equal e?
 2 years ago
 2 years ago
TomLikesPhysics Group Title
If I have a function: y=K*e^x is there a way to rewrite it as y=C*A^x where A does not equal e?
 2 years ago
 2 years ago

This Question is Closed

experimentX Group TitleBest ResponseYou've already chosen the best response.1
let, A^i = e i = 1/lnA
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
it will be the same nevertheless, however I am not sure about K and C
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
I´m just wondering if e is such a magical number to appear here and there or if its artificial and we could use a different set of numbers to express the same thing/physical law.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
i think e is quite an special number < especially when rate of change depends on initial value. also it has some special property (base of natural log), i think it is best to leave things with e's
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
also stretching or compressing exponential function gives e at some point
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
Hmmm what is so special about e? I only know that the derivative of e^x is again e^x which is quite nice and that I can rewrite e^(ix) in terms of sine and cosine but is there even more to e?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
LOL ... not really sure!!
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
xD I thought there might be some additional stuff I might not know about.^^
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
Medals 0 You can do it by writing e as a^(1/ln(a)) and apply exponential identities but why would you want to? e is such a nice number :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
e's the best ... LOL
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
From a practical point of view, if you need to differentiate or integrate your function down the road, would you rather deal with e^x or A^x?
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
@beginnersmind I was wondering if the appearance of e in some laws of physics was because somewhat had the hearts for e or because there is no other way to state that law. Might have been just some physicist who loved e and we could rewrite some laws. Ok than I guess e really is that great. :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
comes naturally from \( \int 1/x dx \)
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
f I integrate or differentiate I am always happy to encounter e ;) But if I just add and multiply I could live without e ;) So it depends on the field.
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
well, a lot of laws are actually of the form e^Cx, so I'm not sure e is especially preferred by nature in those cases. It seems to be notational .
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
So I could easily rewrite y=K*e^(Cx) with some other base?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
i've usually encountered in decay equation and distribution function. decay equation < dN/dt = N < depends on initial value distribution function > didn't understand
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
I started wondering while looking at the decay equation like 10 Minutes ago.^^
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
@experimentX in the decay function the choice of the base is somewhat arbitrary. Say you have f(t)=e^(Ct). You could just as easily write f(t)2^(Kt), with a different constant.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
why ... we choose it as natural base for log while integrating < must be some reason.
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
I'm saying e^(Ct) and 2^(Ct/ln2) are the same function. They take the same values.
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
2^(Ct/ln2) that is
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
But If you rewrite it using the ln than e is still in there (in that function). So you can rewrite in a way that you can not see e but it is hidden in the ln.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
we could use the same logic everywhere, the point is why e so that there is no logs on the power?? 1/ ln 2 ??
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
Well, there's a constant, which is an experimentally determined number. When you use e as the base the constant is C. When you use 2 it's K=C/ln2. If you actually measure halflife you're measuring K, so ln2 isn't really "hidden" there.
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
Ops right. ln2 is just some number  there is not an e hidden. So we could really rewrite equations that fit that pattern.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
not really sure if i am understanding ..:(
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
@experimentX Which part? You wrote the same thing as beginnersmind with the rewriting 1/lnA or now 1/ln2.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
e^x/nothing < why nothing in this case?? must be some special property of e A^x/lnA
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
Why e^x/nothing? Who wrote that where?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
usually equation comes that way when we integrate 1/x dx Oo, i think i need to review decay equation, since i ignored \( \lamda \) factor completely.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
LOL ... seems like only e is nice to deal with,
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
:) I guess than everything is alright. What a nice and interesting discussion. If you follow mathematics and physics in class it seems that e is mysteriously everywhere but apparently it is that way because some people are secretly working for e and we could write it in a different way. :) Nevertheless e is a great number for calculus.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
yeah ... that i agree!! makes nice, easy and clean.
 2 years ago

beginnersmind Group TitleBest ResponseYou've already chosen the best response.1
To be fair, there are situations where e appears in its own right. E.g. you can't rewrite e^i*pi=1 with any number. (I think)
 2 years ago
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