Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

pythagoras123 Group Title

Solve this algebraic equation, and show your working step-by-step. \[\frac{180}{v}\] + \[\frac{9v -180}{1.2v}\] = 8

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. pythagoras123 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Solve for v.

    • 2 years ago
  2. Mertsj Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Multiply each term by the common denominator 1.2v

    • 2 years ago
  3. Mertsj Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[180(1.2)+9v-180=8(1.2v)\]

    • 2 years ago
  4. pythagoras123 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    How...? I tried but I don't know how to Could you show step-by-step working Thanks. :)

    • 2 years ago
  5. pythagoras123 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok thanks

    • 2 years ago
  6. Mertsj Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yw

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.