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me123456789

  • 2 years ago

the beginning of 1975 the population of a country was 40 million and growing at a rate of 3% per year. Assume that the growth is exponential. Estimate the population of the country at the beginning of the year 2010

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  1. Rohangrr
    • 2 years ago
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    of course 80 million

  2. me123456789
    • 2 years ago
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    im sorry and how did you get this?

  3. me123456789
    • 2 years ago
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    plz help

  4. mubzz
    • 2 years ago
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    This can be taken as a geometric progression where the population at any given year is given by \[ar ^{n-1}\] where a is starting population and 'r' in this case is 1.03 as the population is increasing. Now count the years, from 1975 to 2010, 35 years. So you use formula population = \[40000000\times1.03^{35}\] population approx 112 million

  5. me123456789
    • 2 years ago
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    i got 83751117 how did you get 112 mil?

  6. mubzz
    • 2 years ago
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    how did you get that? Because I've used exponential population growth method and geometric progression and got the same answer

  7. me123456789
    • 2 years ago
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    ok i rechecked it ant got 1.05 and the answer was 135mil

  8. mubzz
    • 2 years ago
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    ok let me g through it again. two mins :)

  9. me123456789
    • 2 years ago
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    40000000*1.05^24 was 129003997.7

  10. mubzz
    • 2 years ago
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    it can't be 1.05 as you gave the growth rate to be 3% If it is 5%, then you get 40(1.05)^35 = 220 million Check your question again. You get 135 million if the growth rate is 5% and the time period is 1975 to 2000

  11. me123456789
    • 2 years ago
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    yeah the years are 1975 to 2010

  12. me123456789
    • 2 years ago
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    nm

  13. me123456789
    • 2 years ago
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    can you help me with this one?

  14. me123456789
    • 2 years ago
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    If the population of bacteria doubles in 4 hours how long will it take for it to triple its original size

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