## IsTim 3 years ago Determine dy/dx for y=5sqrt(x^3)

1. CoCoTsoi

y=5sqrt(x^3) = 5(x^(3/2)) dy/dx = 5(3/2)(x^(3/2 -1)) = 15/2 (x^1/2)

2. Ishaan94

IsTim now you're here for math too? giggle, shiny and math?

3. CoCoTsoi

y=x^n dy/dx = nx^(n-1) this is the property I use

4. IsTim

Truly, I don't really understand what derivatives is. @Ishaan94 Pardon?

5. IsTim

The Power Rule. Ok.

6. Ishaan94

Sorry.

7. IsTim

It's ok. I don't understand (your speech and derivatives; either/or) though.

8. IsTim

If you can, please describe each step thoroughly. Thank you.

9. IsTim

OH well.

10. IsTim

What's happening at dy/dx = 5(3/2)(x^(3/2 -1)) ?

11. IsTim

Or, how did it come to that?

12. CoCoTsoi

y=ax^n dy/dx =a( nx^(n-1)) put a=1 and n=3/2

13. IsTim

Uhm, sorry to ask, but could you type dy/dx = 5(3/2)(x^(3/2 -1)) in Latex (The Equation Editor)? I don't think I'm understanding it correctly.

14. IsTim

@CoCoTsoi When you have time, of course.

15. CoCoTsoi

|dw:1335423732321:dw|

16. IsTim

Thanks.

17. Maekin

|dw:1335423870842:dw||dw:1335423900291:dw|

18. Maekin

That was just showing you an of how to work the power rule. I rewrote the sqrt as x^1/2

19. IsTim

|dw:1335434722081:dw| That was the answer in the textbook. How do I convert to that?

20. Maekin

A-ha, that wasn't 5 times sqrt X (etc...) It was the fifth root

21. Maekin

|dw:1335424089162:dw| was the original question

22. IsTim

Yes.