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- IsTim

Determine dy/dx for y=5sqrt(x^3)

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- IsTim

Determine dy/dx for y=5sqrt(x^3)

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- anonymous

y=5sqrt(x^3)
= 5(x^(3/2))
dy/dx = 5(3/2)(x^(3/2 -1))
= 15/2 (x^1/2)

- anonymous

IsTim now you're here for math too? giggle, shiny and math?

- anonymous

y=x^n
dy/dx = nx^(n-1)
this is the property I use

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- IsTim

Truly, I don't really understand what derivatives is.
@Ishaan94 Pardon?

- IsTim

The Power Rule. Ok.

- anonymous

Sorry.

- IsTim

It's ok. I don't understand (your speech and derivatives; either/or) though.

- IsTim

If you can, please describe each step thoroughly. Thank you.

- IsTim

OH well.

- IsTim

What's happening at dy/dx = 5(3/2)(x^(3/2 -1)) ?

- IsTim

Or, how did it come to that?

- anonymous

y=ax^n
dy/dx =a( nx^(n-1))
put a=1 and n=3/2

- IsTim

Uhm, sorry to ask, but could you type dy/dx = 5(3/2)(x^(3/2 -1)) in Latex (The Equation Editor)? I don't think I'm understanding it correctly.

- IsTim

@CoCoTsoi When you have time, of course.

- anonymous

|dw:1335423732321:dw|

- IsTim

Thanks.

- anonymous

|dw:1335423870842:dw||dw:1335423900291:dw|

- anonymous

That was just showing you an of how to work the power rule. I rewrote the sqrt as x^1/2

- IsTim

|dw:1335434722081:dw|
That was the answer in the textbook. How do I convert to that?

- anonymous

A-ha, that wasn't 5 times sqrt X (etc...) It was the fifth root

- anonymous

|dw:1335424089162:dw| was the original question

- IsTim

Yes.

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