anonymous
  • anonymous
Find the indefinite integral.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\int\limits_{?}^{?}xsin3x^2dx\]
anonymous
  • anonymous
so if i were using u substitution u = 3x^2??
anonymous
  • anonymous
du/dt=6x??

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anonymous
  • anonymous
an du/6=xdx?
anonymous
  • anonymous
Yes you are right @ChrisV You get \[\int\limits_{}^{} \sin (u) du = -\cos (u) +C\] \[-\cos(u) +C = -\cos(3x^2 / 2) +C\]
amistre64
  • amistre64
i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless
anonymous
  • anonymous
I forgot to divide the answer by 6
anonymous
  • anonymous
And also it is only 3x^2 and not 3x^2/2 . Sorry :P
anonymous
  • anonymous
-1/6cos3x^2 +c
anonymous
  • anonymous
?
anonymous
  • anonymous
Yes you are right @ChrisV

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