## anonymous 4 years ago Find the indefinite integral.

1. anonymous

$\int\limits_{?}^{?}xsin3x^2dx$

2. anonymous

so if i were using u substitution u = 3x^2??

3. anonymous

du/dt=6x??

4. anonymous

an du/6=xdx?

5. anonymous

Yes you are right @ChrisV You get $\int\limits_{}^{} \sin (u) du = -\cos (u) +C$ $-\cos(u) +C = -\cos(3x^2 / 2) +C$

6. amistre64

i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless

7. anonymous

I forgot to divide the answer by 6

8. anonymous

And also it is only 3x^2 and not 3x^2/2 . Sorry :P

9. anonymous

-1/6cos3x^2 +c

10. anonymous

?

11. anonymous

Yes you are right @ChrisV