ChrisV
Find the indefinite integral.



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ChrisV
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\[\int\limits_{?}^{?}xsin3x^2dx\]

ChrisV
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so if i were using u substitution u = 3x^2??

ChrisV
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du/dt=6x??

ChrisV
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an du/6=xdx?

shivam_bhalla
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Yes you are right @ChrisV
You get
\[\int\limits_{}^{} \sin (u) du = \cos (u) +C\]
\[\cos(u) +C = \cos(3x^2 / 2) +C\]

amistre64
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i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless

shivam_bhalla
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I forgot to divide the answer by 6

shivam_bhalla
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And also it is only 3x^2 and not 3x^2/2 . Sorry :P

ChrisV
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1/6cos3x^2 +c

ChrisV
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?

shivam_bhalla
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Yes you are right @ChrisV