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ChrisV

  • 4 years ago

Find the indefinite integral.

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  1. ChrisV
    • 4 years ago
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    \[\int\limits_{?}^{?}xsin3x^2dx\]

  2. ChrisV
    • 4 years ago
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    so if i were using u substitution u = 3x^2??

  3. ChrisV
    • 4 years ago
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    du/dt=6x??

  4. ChrisV
    • 4 years ago
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    an du/6=xdx?

  5. shivam_bhalla
    • 4 years ago
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    Yes you are right @ChrisV You get \[\int\limits_{}^{} \sin (u) du = -\cos (u) +C\] \[-\cos(u) +C = -\cos(3x^2 / 2) +C\]

  6. amistre64
    • 4 years ago
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    i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless

  7. shivam_bhalla
    • 4 years ago
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    I forgot to divide the answer by 6

  8. shivam_bhalla
    • 4 years ago
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    And also it is only 3x^2 and not 3x^2/2 . Sorry :P

  9. ChrisV
    • 4 years ago
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    -1/6cos3x^2 +c

  10. ChrisV
    • 4 years ago
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    ?

  11. shivam_bhalla
    • 4 years ago
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    Yes you are right @ChrisV

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