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ChrisV Group Title

Find the indefinite integral.

  • 2 years ago
  • 2 years ago

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  1. ChrisV Group Title
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    \[\int\limits_{?}^{?}xsin3x^2dx\]

    • 2 years ago
  2. ChrisV Group Title
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    so if i were using u substitution u = 3x^2??

    • 2 years ago
  3. ChrisV Group Title
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    du/dt=6x??

    • 2 years ago
  4. ChrisV Group Title
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    an du/6=xdx?

    • 2 years ago
  5. shivam_bhalla Group Title
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    Yes you are right @ChrisV You get \[\int\limits_{}^{} \sin (u) du = -\cos (u) +C\] \[-\cos(u) +C = -\cos(3x^2 / 2) +C\]

    • 2 years ago
  6. amistre64 Group Title
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    i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless

    • 2 years ago
  7. shivam_bhalla Group Title
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    I forgot to divide the answer by 6

    • 2 years ago
  8. shivam_bhalla Group Title
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    And also it is only 3x^2 and not 3x^2/2 . Sorry :P

    • 2 years ago
  9. ChrisV Group Title
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    -1/6cos3x^2 +c

    • 2 years ago
  10. ChrisV Group Title
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    ?

    • 2 years ago
  11. shivam_bhalla Group Title
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    Yes you are right @ChrisV

    • 2 years ago
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