anonymous
  • anonymous
The area of a regular hexagon is 50 square inches. What is the area of a regular hexagon with side lengths twice as long as the sides of the first regular hexagon?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[A = (3\sqrt{3}*t ^{2})\div2\] Where t is the length of one side. In your case, you know the area but you don't know t. So you can solve for 't' and you get t = 4.3869 for the second hexagon, t = 8.7738 So plug this value of t in the original formaula and you get area as 199.99 Area is approx. 200

Looking for something else?

Not the answer you are looking for? Search for more explanations.