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How did you get that triangle?
I drew a triangle and use the fact the sin (theta)=-4/5 remember sine is opposite over hypothenuse
Ohhh, thats how you did it, okay!
Now the 5 trig funtions of theta? I thought there were 3 trig functions o.O
now let's find adjacent side value using pythagorean theorem a^2+4^2=5^2 a^2=25-16 a^2=9 a=3
now we can see what cos , and tan are cos is adjacent over hypotenuse cos(theta)= 3/5
Tangent is sin(theta)/cos(theta) -4/5 ------ =-4/3 3/5
Okay, i got those two, what are the other 3 they are looking for?
csc(theta)= 1/sin(theta)= 1 = -5/4 ----- -4/5
sec(theta)= 1/cos(theta)= 1/ (3/5) = 5/3
cot(theta)= 1/tan(theta)= 1/(-4/3) =-3/4
Oh we use the recriprocoals
Ooooo, that makes much more sense!!! Okay, i know how to do the fraction one as we did now, but what about the second one, tan(theta)=2..how do i set that up?
tan(theta)=2=2/1; Quadrant 1 |dw:1335489526582:dw|
use pythagorean theorem to find hypotenuse
Okay, so basically, if its a whole number, we put it as a fraction?
Hypotenuse is square root of 3
Srry, did it in my head, got my trusy calculator :D
Okay, i got it, thanks for helpin :D
anything for my shrink
LOL, i might just pass algebra 2
I took algebra 2 in sophomore year, and it was big deal way back
Im taking it freshman :p
I wish, lol, i just barely pass every time.
pre calc next year and then calculus
arghhh..dont remind me :/ Im taking summer school to prep for it.