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GOODMAN

Suppose (theta sign) is an angle in standard position whose terminal side lies in the given quadrant. For these functions, find the exact values of the remaining five trigonometric funtctions of (theta) sin(theta)=-4/5; Quadrant 4 tan(theta)=2; Quadrant 1

  • one year ago
  • one year ago

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  1. imranmeah91
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    sin(theta)=-4/5 |dw:1335488862320:dw|

    • one year ago
  2. imranmeah91
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    |dw:1335488894071:dw|

    • one year ago
  3. GOODMAN
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    How did you get that triangle?

    • one year ago
  4. imranmeah91
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    I drew a triangle and use the fact the sin (theta)=-4/5 remember sine is opposite over hypothenuse

    • one year ago
  5. GOODMAN
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    Ohhh, thats how you did it, okay!

    • one year ago
  6. GOODMAN
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    Now the 5 trig funtions of theta? I thought there were 3 trig functions o.O

    • one year ago
  7. imranmeah91
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    now let's find adjacent side value using pythagorean theorem a^2+4^2=5^2 a^2=25-16 a^2=9 a=3

    • one year ago
  8. imranmeah91
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    |dw:1335489127010:dw|

    • one year ago
  9. imranmeah91
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    now we can see what cos , and tan are cos is adjacent over hypotenuse cos(theta)= 3/5

    • one year ago
  10. imranmeah91
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    Tangent is sin(theta)/cos(theta) -4/5 ------ =-4/3 3/5

    • one year ago
  11. GOODMAN
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    Okay, i got those two, what are the other 3 they are looking for?

    • one year ago
  12. imranmeah91
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    csc(theta)= 1/sin(theta)= 1 = -5/4 ----- -4/5

    • one year ago
  13. imranmeah91
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    sec(theta)= 1/cos(theta)= 1/ (3/5) = 5/3

    • one year ago
  14. imranmeah91
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    cot(theta)= 1/tan(theta)= 1/(-4/3) =-3/4

    • one year ago
  15. GOODMAN
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    Oh we use the recriprocoals

    • one year ago
  16. imranmeah91
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    yep

    • one year ago
  17. GOODMAN
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    Ooooo, that makes much more sense!!! Okay, i know how to do the fraction one as we did now, but what about the second one, tan(theta)=2..how do i set that up?

    • one year ago
  18. imranmeah91
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    tan(theta)=2=2/1; Quadrant 1 |dw:1335489526582:dw|

    • one year ago
  19. imranmeah91
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    use pythagorean theorem to find hypotenuse

    • one year ago
  20. GOODMAN
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    Okay, so basically, if its a whole number, we put it as a fraction?

    • one year ago
  21. imranmeah91
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    yes

    • one year ago
  22. GOODMAN
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    Hypotenuse is square root of 3

    • one year ago
  23. imranmeah91
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    sqrt[2^2+1^2]=sqrt[5]

    • one year ago
  24. GOODMAN
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    Srry, did it in my head, got my trusy calculator :D

    • one year ago
  25. GOODMAN
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    Okay, i got it, thanks for helpin :D

    • one year ago
  26. imranmeah91
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    anything for my shrink

    • one year ago
  27. GOODMAN
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    LOL, i might just pass algebra 2

    • one year ago
  28. imranmeah91
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    I took algebra 2 in sophomore year, and it was big deal way back

    • one year ago
  29. GOODMAN
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    Im taking it freshman :p

    • one year ago
  30. imranmeah91
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    smartie

    • one year ago
  31. GOODMAN
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    I wish, lol, i just barely pass every time.

    • one year ago
  32. imranmeah91
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    pre calc next year and then calculus

    • one year ago
  33. GOODMAN
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    arghhh..dont remind me :/ Im taking summer school to prep for it.

    • one year ago
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