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Suppose (theta sign) is an angle in standard position whose terminal side lies in the given quadrant. For these functions, find the exact values of the remaining five trigonometric funtctions of (theta) sin(theta)=-4/5; Quadrant 4 tan(theta)=2; Quadrant 1

Mathematics
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sin(theta)=-4/5 |dw:1335488862320:dw|
|dw:1335488894071:dw|
How did you get that triangle?

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Other answers:

I drew a triangle and use the fact the sin (theta)=-4/5 remember sine is opposite over hypothenuse
Ohhh, thats how you did it, okay!
Now the 5 trig funtions of theta? I thought there were 3 trig functions o.O
now let's find adjacent side value using pythagorean theorem a^2+4^2=5^2 a^2=25-16 a^2=9 a=3
|dw:1335489127010:dw|
now we can see what cos , and tan are cos is adjacent over hypotenuse cos(theta)= 3/5
Tangent is sin(theta)/cos(theta) -4/5 ------ =-4/3 3/5
Okay, i got those two, what are the other 3 they are looking for?
csc(theta)= 1/sin(theta)= 1 = -5/4 ----- -4/5
sec(theta)= 1/cos(theta)= 1/ (3/5) = 5/3
cot(theta)= 1/tan(theta)= 1/(-4/3) =-3/4
Oh we use the recriprocoals
yep
Ooooo, that makes much more sense!!! Okay, i know how to do the fraction one as we did now, but what about the second one, tan(theta)=2..how do i set that up?
tan(theta)=2=2/1; Quadrant 1 |dw:1335489526582:dw|
use pythagorean theorem to find hypotenuse
Okay, so basically, if its a whole number, we put it as a fraction?
yes
Hypotenuse is square root of 3
sqrt[2^2+1^2]=sqrt[5]
Srry, did it in my head, got my trusy calculator :D
Okay, i got it, thanks for helpin :D
anything for my shrink
LOL, i might just pass algebra 2
I took algebra 2 in sophomore year, and it was big deal way back
Im taking it freshman :p
smartie
I wish, lol, i just barely pass every time.
pre calc next year and then calculus
arghhh..dont remind me :/ Im taking summer school to prep for it.

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