anonymous
  • anonymous
Suppose (theta sign) is an angle in standard position whose terminal side lies in the given quadrant. For these functions, find the exact values of the remaining five trigonometric funtctions of (theta) sin(theta)=-4/5; Quadrant 4 tan(theta)=2; Quadrant 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sin(theta)=-4/5 |dw:1335488862320:dw|
anonymous
  • anonymous
|dw:1335488894071:dw|
anonymous
  • anonymous
How did you get that triangle?

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anonymous
  • anonymous
I drew a triangle and use the fact the sin (theta)=-4/5 remember sine is opposite over hypothenuse
anonymous
  • anonymous
Ohhh, thats how you did it, okay!
anonymous
  • anonymous
Now the 5 trig funtions of theta? I thought there were 3 trig functions o.O
anonymous
  • anonymous
now let's find adjacent side value using pythagorean theorem a^2+4^2=5^2 a^2=25-16 a^2=9 a=3
anonymous
  • anonymous
|dw:1335489127010:dw|
anonymous
  • anonymous
now we can see what cos , and tan are cos is adjacent over hypotenuse cos(theta)= 3/5
anonymous
  • anonymous
Tangent is sin(theta)/cos(theta) -4/5 ------ =-4/3 3/5
anonymous
  • anonymous
Okay, i got those two, what are the other 3 they are looking for?
anonymous
  • anonymous
csc(theta)= 1/sin(theta)= 1 = -5/4 ----- -4/5
anonymous
  • anonymous
sec(theta)= 1/cos(theta)= 1/ (3/5) = 5/3
anonymous
  • anonymous
cot(theta)= 1/tan(theta)= 1/(-4/3) =-3/4
anonymous
  • anonymous
Oh we use the recriprocoals
anonymous
  • anonymous
yep
anonymous
  • anonymous
Ooooo, that makes much more sense!!! Okay, i know how to do the fraction one as we did now, but what about the second one, tan(theta)=2..how do i set that up?
anonymous
  • anonymous
tan(theta)=2=2/1; Quadrant 1 |dw:1335489526582:dw|
anonymous
  • anonymous
use pythagorean theorem to find hypotenuse
anonymous
  • anonymous
Okay, so basically, if its a whole number, we put it as a fraction?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Hypotenuse is square root of 3
anonymous
  • anonymous
sqrt[2^2+1^2]=sqrt[5]
anonymous
  • anonymous
Srry, did it in my head, got my trusy calculator :D
anonymous
  • anonymous
Okay, i got it, thanks for helpin :D
anonymous
  • anonymous
anything for my shrink
anonymous
  • anonymous
LOL, i might just pass algebra 2
anonymous
  • anonymous
I took algebra 2 in sophomore year, and it was big deal way back
anonymous
  • anonymous
Im taking it freshman :p
anonymous
  • anonymous
smartie
anonymous
  • anonymous
I wish, lol, i just barely pass every time.
anonymous
  • anonymous
pre calc next year and then calculus
anonymous
  • anonymous
arghhh..dont remind me :/ Im taking summer school to prep for it.

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