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 2 years ago
Find the general solution \[{dP \over dt} = 0.08P\left(1{P \over 1000} \right) 15\]
 2 years ago
Find the general solution \[{dP \over dt} = 0.08P\left(1{P \over 1000} \right) 15\]

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gmer
 2 years ago
Best ResponseYou've already chosen the best response.0I started by multpling and factoring the right side

gmer
 2 years ago
Best ResponseYou've already chosen the best response.0then it became seperable and I ended up with \[\int{25 \over P  250}  {25 \over P  750} dP =  \int dt\] after partial fractions

gmer
 2 years ago
Best ResponseYou've already chosen the best response.0\[25 \ln {P  250 \over P  750} = t + c\] how do I solve this thing for P?

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0Do you need to make it into a P= something form? Because that one up there is already a considerable final answer, in my opinion.

gmer
 2 years ago
Best ResponseYou've already chosen the best response.0It's a population growth equation, i need to use it to solve for some populations
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