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gmer
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Find the general solution \[{dP \over dt} = 0.08P\left(1{P \over 1000} \right) 15\]
 2 years ago
 2 years ago
gmer Group Title
Find the general solution \[{dP \over dt} = 0.08P\left(1{P \over 1000} \right) 15\]
 2 years ago
 2 years ago

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gmer Group TitleBest ResponseYou've already chosen the best response.0
I started by multpling and factoring the right side
 2 years ago

gmer Group TitleBest ResponseYou've already chosen the best response.0
then it became seperable and I ended up with \[\int{25 \over P  250}  {25 \over P  750} dP =  \int dt\] after partial fractions
 2 years ago

gmer Group TitleBest ResponseYou've already chosen the best response.0
\[25 \ln {P  250 \over P  750} = t + c\] how do I solve this thing for P?
 2 years ago

imagreencat Group TitleBest ResponseYou've already chosen the best response.0
Do you need to make it into a P= something form? Because that one up there is already a considerable final answer, in my opinion.
 2 years ago

gmer Group TitleBest ResponseYou've already chosen the best response.0
It's a population growth equation, i need to use it to solve for some populations
 2 years ago
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