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Chena804
 3 years ago
Solve. Please show steps.
lnxln(x1)=1
Chena804
 3 years ago
Solve. Please show steps. lnxln(x1)=1

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lalaly
 3 years ago
Best ResponseYou've already chosen the best response.3use \[\ln(\frac{a}{b})=lnalnb\]

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2then use \(\large \log_a b = c \rightarrow a^c = b\)

lalaly
 3 years ago
Best ResponseYou've already chosen the best response.3easier way take e of both sides since its ln

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.2as the queen orders... \(\ln a = x \rightarrow e^x = a\)

thunderemperor
 3 years ago
Best ResponseYou've already chosen the best response.0\[\ln x\ln (x1)=1\] \[\ln (x \div(x1))=1\] \[\left(\begin{matrix}x\\ x1\end{matrix}\right)=e ^{1}\] \[x=(x1)e ^{1}\] You can solve the rest. ;)
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