Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

shivam_bhalla

  • 2 years ago

See the question in diagram My question is what is the pressure felt by the wall Wait for diagram

  • This Question is Closed
  1. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1335593779148:dw| P-->Pressure applied on wall of cylinder Assume one side of the cylinder is filled with liquid as in figure i) Does P vary with depth of cylinder ii)How do you get P?

  2. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Aditya790 . Any tip?

  3. mos1635
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    are we looking for pressure or total force???

  4. Aditya790
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @shivam_bhalla Pressure increases linearly with depth, the exact relation being P=pgh. In this problem, the density is same and gravitational constant is also same. The only thing that varies the pressure down the wall is how deep we go. From the figure, the wall is h units high and 2r units in width. At the top of the wall, the pressure is 0 (p*g*0) and at the bottom it is pgh. Since it increases linearly, we can use the average value of pressure that is pgh/2 as the pressure on the entire wall. The area of the wall is 2rh. So the force on the wall is (pgh/2)*(2rh), this is pressure times area. Alternately, you can divide the wall into horizontal strips of height dh and length 2r. the force on a particular segment at a depth of h is 2rpghdh. You can find the total force by integrating this expression from 0 to H. I wouldn't recommend this though because it is a longer method. Remember in general that for a quantity changing linearly, you can use the average value to represent the quantity at any instance. We do this in constantly accelerated motion where u is initial velocity and v is final velocity. We can compute distance by (u+v)/2 * time.

  5. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    At the top of the wall, the pressure is 0 (p*g*0) -->how, what about surface tension??

  6. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    We have the force, but the area would be negligigble? Am I right @Aditya790

  7. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    And so pressure due to surface tension-->Almost absent

  8. Aditya790
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @shivam_bhalla Yes. Compared to the pressure, surface tension is a very small value. At 20 degrees centigrade, the force due to suface tension is on the top is 0.0727*2r newton, which is very slight. Nice point though, I never considered surface tension in such a case. Since the surface tension acts only on the top, it causes a torque inward. To weak to cause a steel/glass vessal to break. But if you pour water into a non-rigid container like a plastic cover, the cover kind of closes up on the top and the body of the cover becomes spherical in shape (sphere has minimum surface area for a given volume) as water tries to minimise its surface area. Thanks for bringing my attention to it.

  9. shivam_bhalla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Aditya790 , You are a computer or what :P . Great work :)

  10. Aditya790
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @shivam_bhalla Not really, but thanks. Always feels good to be appreciated.

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.