Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lgbasallote
Group Title
\(\large \mathbf{\color{maroon}{L} \color{violet}{G} \color{orange}{B} \color{darkblue}{A} \color{gold}{R} \color{brown}{I} \color{pink}{D} \color{purple}{D} \color{green}{L} \color{white}{E}}\)
\(\LARGE \int \frac{1}{\sqrt x  \sqrt[3]{x}}dx\)
Hint: Be Creative!
 2 years ago
 2 years ago
lgbasallote Group Title
\(\large \mathbf{\color{maroon}{L} \color{violet}{G} \color{orange}{B} \color{darkblue}{A} \color{gold}{R} \color{brown}{I} \color{pink}{D} \color{purple}{D} \color{green}{L} \color{white}{E}}\) \(\LARGE \int \frac{1}{\sqrt x  \sqrt[3]{x}}dx\) Hint: Be Creative!
 2 years ago
 2 years ago

This Question is Closed

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
@Ishaan94
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
this is very easy once you found the first step :P
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
hint please; i don't want to go on the track...what substitution?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
if i say the substitution then it's already solved :P that's the key haha
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
shhh hero :S
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I didn't say anything relevant :P
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i assume you found the substitution already..
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I'm not saying anything :P
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
let u =x^(1/3) ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
haha no mimi ^_^
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
well, times the denominator and numerator by something? i dont want to go on the wrong track it will get messy
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
nope either :) just a simple u substitution
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
u= x^(1/2) ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
still no :p haha
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
u =x^(1/6) ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
yup! yay :D now solve it >:))
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
lol, then its long division too lazy
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hahaha =)) that's why it's an lgbariddle ;D
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Let, Hero do it.. :P
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
Take u =x^(1/6) and then go ahead with partial fraction . Tiring :P
 2 years ago

blockcolder Group TitleBest ResponseYou've already chosen the best response.0
Yeah. That's the only way to do it (I think).
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
ahh the beauty of lgbariddles >:))
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
No it is plum \[\int\limits_{}^{} \large \frac{6u^5} {u^2(u1)}\] \[\large 6\int\limits_{}^{}\frac{u^3}{u1} = \large 6\int\limits_{}^{}\frac{u^31^3}{u1} +6\int\limits_{}^{}\frac{1}{u1}\] Now continue :D
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
Answer should come within 2 steps :D
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
shivam you have nnothing now :P
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
lol. I forgot du everywhere :P
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
lol du= whatever :P
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
"shivam you have nnothing now :P ">????
 2 years ago

blockcolder Group TitleBest ResponseYou've already chosen the best response.0
Is the first integral an arctan of something?
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
You got to be kidding me @blockcolder just apply u^31^3 = (u1)(u^2+1+u) and cancel the numerator u1 and denominator u1
 2 years ago

blockcolder Group TitleBest ResponseYou've already chosen the best response.0
And then complete the square of the denominator and viola! A wild arctan appears!
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
@blockcolder \[\large 6\int\limits\limits_{}^{}{(u^2+1+u)}du +6\int\limits\limits_{}^{}\frac{1}{u1}\] \[\large 6u^3/3 + 6u+ 3u^2 + 6\log(u1)\]
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.3
substitute u= x^(1/6) and voila :P
 2 years ago

blockcolder Group TitleBest ResponseYou've already chosen the best response.0
Oh, right. I thought the u^31 is in the denominator. Guess I should clean my glasses.
 2 years ago

blockcolder Group TitleBest ResponseYou've already chosen the best response.0
Yeah, that happens a lot with me. =))
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.