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x^5(x-2)^2=0

ok i cant read. start with \[x^5(x-2)^2\] and multiply out

so I would get \[x ^{5}+x ^{2}-4x+4\]

no i don't think so

\[x^5(x-2)^2=x^5(x-2)(x-2)=...\]

where does the extra (x-2)^2 come from then that you have after the x^5?

oh nvm.... so what am I multiplying out then? the (x-2)^2 or?

\[x^5(x-)(x-2)=x^5(x^2-4x+4)=x^7-4x^6+4x^5\]

Yes

awesome thanks so much for the help!

yw

NVM I figured it out:) thanks

i wouldn't

oh looks like you got it right? start with \((3x-1)^2\)

Thanks:)