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mariomintchev

For #9, will I always get the right answer if I take the volume (32), divide it by the pressure (4), and multiply it by the rate (2)?

  • one year ago
  • one year ago

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  1. mariomintchev
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    • one year ago
  2. mariomintchev
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    Because I get the right answer doing that with this problem...

    • one year ago
  3. KingGeorge
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    I don't think so. I'm pretty sure that's an artifact of \(2^2=4\). Or something similar.

    • one year ago
  4. mariomintchev
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    what do you mean?

    • one year ago
  5. KingGeorge
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    Well, if we do the actual problem out, we get that \(c=128\). Then, we have that \[dV=-\;{128 \over P^2} dP\]We know that \(dP =2\) and \(P=4\). Solving, we find that \(dV =-16\). So really, it seems like it's because everything is just a power of two.

    • one year ago
  6. mariomintchev
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    i see

    • one year ago
  7. KingGeorge
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    For a counterexample, let \(V=40\). Then we get that \(dV =-35/2\) using the method I wrote out. Using your hypothetical method, we get that it would be \(-20\).

    • one year ago
  8. mariomintchev
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    haha i like creating my own ways to solve things.

    • one year ago
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