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krystabell

Find II 2e-3f II assuming that e & f are unit vectors such that II e +f II=sqrt(3/2).I tried using the law of cosines but not getting it...

  • one year ago
  • one year ago

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  1. beginnersmind
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    Draw e+f, and solve for the angle.

    • one year ago
  2. beginnersmind
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    Do you need another hint?

    • one year ago
  3. krystabell
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    not yet, doing math & watching my 3year old and 1 year old sister is interesting...makes solving problems kind of slow...i'll post if i need another hint thanks!

    • one year ago
  4. beginnersmind
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    Ok, sometimes people get stuck but don't speak up until you ask :(

    • one year ago
  5. krystabell
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    why am I finding the theta between e & e+f....theta=e dot e+f / sqrt(3/2)...

    • one year ago
  6. beginnersmind
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    You need theta between e and f.|dw:1335665267401:dw|

    • one year ago
  7. krystabell
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    but then theta=e dot f what is that...

    • one year ago
  8. beginnersmind
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    Where is e+f on the picture? You have a triangle and you know the length of all 3 sides.

    • one year ago
  9. krystabell
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    |dw:1335665495008:dw|

    • one year ago
  10. krystabell
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    got it got it got it....

    • one year ago
  11. krystabell
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    thanks!!!

    • one year ago
  12. beginnersmind
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    ok, that saves me some drawing :)

    • one year ago
  13. krystabell
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    now i can move on lol i hope that you aren't much younger than me, i'm very competitive but i gotta hand it to you! idk why I got stumped i tutor calc 3!!! >:/

    • one year ago
  14. beginnersmind
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    I'm probably not :)

    • one year ago
  15. eliassaab
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    \[ (e+f) . (e+f)=e.e + e.f + f.e + f.f=2 +2 e.f= \frac 32\\ e.f =-\frac 1 4\\ (2e -3f).(2e-3f)=4e.e - 6 e.f -6 f.e +9f.f =\\ 13 - 12 e.f= 13 + 3=16\\ || 2e - 3f|| =\sqrt{(2e -3f).(2e-3f)} =\sqrt {16}=4 \] where u.v is the dot product of u and v

    • one year ago
  16. beginnersmind
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    Wow, that's actually nicer than calculating the angle between e and f and writing them in a new coordinate system.

    • one year ago
  17. eliassaab
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    Actually for any m and n || m e - n f|| can be calculated and depends only on m and n and e.f

    • one year ago
  18. krystabell
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    awesome eliassaab!!!

    • one year ago
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