Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find II 2e-3f II assuming that e & f are unit vectors such that II e +f II=sqrt(3/2).I tried using the law of cosines but not getting it...

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Draw e+f, and solve for the angle.
Do you need another hint?
not yet, doing math & watching my 3year old and 1 year old sister is interesting...makes solving problems kind of slow...i'll post if i need another hint thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Ok, sometimes people get stuck but don't speak up until you ask :(
why am I finding the theta between e & e+f....theta=e dot e+f / sqrt(3/2)...
You need theta between e and f.|dw:1335665267401:dw|
but then theta=e dot f what is that...
Where is e+f on the picture? You have a triangle and you know the length of all 3 sides.
|dw:1335665495008:dw|
got it got it got it....
thanks!!!
ok, that saves me some drawing :)
now i can move on lol i hope that you aren't much younger than me, i'm very competitive but i gotta hand it to you! idk why I got stumped i tutor calc 3!!! >:/
I'm probably not :)
\[ (e+f) . (e+f)=e.e + e.f + f.e + f.f=2 +2 e.f= \frac 32\\ e.f =-\frac 1 4\\ (2e -3f).(2e-3f)=4e.e - 6 e.f -6 f.e +9f.f =\\ 13 - 12 e.f= 13 + 3=16\\ || 2e - 3f|| =\sqrt{(2e -3f).(2e-3f)} =\sqrt {16}=4 \] where u.v is the dot product of u and v
Wow, that's actually nicer than calculating the angle between e and f and writing them in a new coordinate system.
Actually for any m and n || m e - n f|| can be calculated and depends only on m and n and e.f
awesome eliassaab!!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question