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mmbuckaroos Group Title

Determine all of the roots of the given equation: x^3-2x^2-3x+10=0

  • 2 years ago
  • 2 years ago

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  1. shelovespiano Group Title
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    Complex, too? @mmbuckaroos?

    • 2 years ago
  2. shelovespiano Group Title
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    x=-2 x=2-i x=2+i

    • 2 years ago
  3. mmbuckaroos Group Title
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    Could you explaint o me how you got those so I can try my other problems please?

    • 2 years ago
  4. shelovespiano Group Title
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    Sorry, I'm a little low on time... if you bump your question, i'm sure someone else can help you. sorry!

    • 2 years ago
  5. mmbuckaroos Group Title
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    ok thanks

    • 2 years ago
  6. Mertsj Group Title
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    The possible rational roots are the factors of the constant term which is 10 divided by the factors of the coefficient of the term with the highest exponent which is the x^3 term. It's coefficient is 1. So the possible rational roots are: \[\frac{\pm10}{1}, \frac{\pm5}{1}, \pm\frac{2}{1}, \frac{\pm1}{1}\]

    • 2 years ago
  7. Mertsj Group Title
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    Use synthetic division to see if any of those are actually roots.

    • 2 years ago
  8. Mertsj Group Title
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    Since we have reason to believe that -2 is a root, let's try it.

    • 2 years ago
  9. Mertsj Group Title
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    |dw:1335664232988:dw|

    • 2 years ago
  10. Mertsj Group Title
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    So we see that -2 is a root and now we must solve the quadratic equation x^2-4x+5=0 to find the other roots.

    • 2 years ago
  11. mmbuckaroos Group Title
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    ok this is the part that confuses me this division. My book here makes it so confusing

    • 2 years ago
  12. mmbuckaroos Group Title
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    like where do you get all of those numbers from? Sorry I just don't get this at all.

    • 2 years ago
  13. Mertsj Group Title
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    |dw:1335664387666:dw|

    • 2 years ago
  14. Mertsj Group Title
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    So you need help with synthetic division?

    • 2 years ago
  15. Mertsj Group Title
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    Do you understand the part about the possible rational roots?

    • 2 years ago
  16. mmbuckaroos Group Title
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    I actually think I figured out what you did to get those numbers now so nvm on that ? I understand the possible rational roots

    • 2 years ago
  17. Mertsj Group Title
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    So you need help with the synthetic division process?

    • 2 years ago
  18. mmbuckaroos Group Title
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    do i have to do the synthetic division for every possible rational root?

    • 2 years ago
  19. Mertsj Group Title
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    No. Just until you find one where the remainder is 0. That indicates that you have found a factor. Then you can start working on the quotient to find more roots.

    • 2 years ago
  20. mmbuckaroos Group Title
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    so it is a rootif it comes out equaling zero. ok so now that im following you we can keep going sorry about that

    • 2 years ago
  21. Mertsj Group Title
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    |dw:1335664711981:dw|

    • 2 years ago
  22. Mertsj Group Title
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    So since the second factor is a quadratic and it won't factor, we just plug it into the formula to find the roots.

    • 2 years ago
  23. Mertsj Group Title
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    Do you have another problem? Perhaps if we start another one from scratch, it will help you understand. I can guide you.

    • 2 years ago
  24. mmbuckaroos Group Title
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    yes one sec sorry

    • 2 years ago
  25. mmbuckaroos Group Title
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    x^3-x^2-4x-6=0

    • 2 years ago
  26. Mertsj Group Title
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    Can you list the possible rational roots?

    • 2 years ago
  27. Mertsj Group Title
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    It is so hard to help someone who won't respond.

    • 2 years ago
  28. mmbuckaroos Group Title
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    Sorry my computer shut down. Ok: +/-1, +/-1/6 ?

    • 2 years ago
  29. shelovespiano Group Title
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    He's not online anymore.... btw. I don't think I can help you, though, sorry:/ bump your question i guess?

    • 2 years ago
  30. mmbuckaroos Group Title
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    It's alright. I think I got it figured out. Feel bad I left him hanging there darn computer for some reason it doesn't ever like this site

    • 2 years ago
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