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mmbuckaroos

Determine all of the roots of the given equation: x^3-2x^2-3x+10=0

  • one year ago
  • one year ago

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  1. shelovespiano
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    Complex, too? @mmbuckaroos?

    • one year ago
  2. shelovespiano
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    x=-2 x=2-i x=2+i

    • one year ago
  3. mmbuckaroos
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    Could you explaint o me how you got those so I can try my other problems please?

    • one year ago
  4. shelovespiano
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    Sorry, I'm a little low on time... if you bump your question, i'm sure someone else can help you. sorry!

    • one year ago
  5. mmbuckaroos
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    ok thanks

    • one year ago
  6. Mertsj
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    The possible rational roots are the factors of the constant term which is 10 divided by the factors of the coefficient of the term with the highest exponent which is the x^3 term. It's coefficient is 1. So the possible rational roots are: \[\frac{\pm10}{1}, \frac{\pm5}{1}, \pm\frac{2}{1}, \frac{\pm1}{1}\]

    • one year ago
  7. Mertsj
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    Use synthetic division to see if any of those are actually roots.

    • one year ago
  8. Mertsj
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    Since we have reason to believe that -2 is a root, let's try it.

    • one year ago
  9. Mertsj
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    |dw:1335664232988:dw|

    • one year ago
  10. Mertsj
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    So we see that -2 is a root and now we must solve the quadratic equation x^2-4x+5=0 to find the other roots.

    • one year ago
  11. mmbuckaroos
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    ok this is the part that confuses me this division. My book here makes it so confusing

    • one year ago
  12. mmbuckaroos
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    like where do you get all of those numbers from? Sorry I just don't get this at all.

    • one year ago
  13. Mertsj
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    |dw:1335664387666:dw|

    • one year ago
  14. Mertsj
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    So you need help with synthetic division?

    • one year ago
  15. Mertsj
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    Do you understand the part about the possible rational roots?

    • one year ago
  16. mmbuckaroos
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    I actually think I figured out what you did to get those numbers now so nvm on that ? I understand the possible rational roots

    • one year ago
  17. Mertsj
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    So you need help with the synthetic division process?

    • one year ago
  18. mmbuckaroos
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    do i have to do the synthetic division for every possible rational root?

    • one year ago
  19. Mertsj
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    No. Just until you find one where the remainder is 0. That indicates that you have found a factor. Then you can start working on the quotient to find more roots.

    • one year ago
  20. mmbuckaroos
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    so it is a rootif it comes out equaling zero. ok so now that im following you we can keep going sorry about that

    • one year ago
  21. Mertsj
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    |dw:1335664711981:dw|

    • one year ago
  22. Mertsj
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    So since the second factor is a quadratic and it won't factor, we just plug it into the formula to find the roots.

    • one year ago
  23. Mertsj
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    Do you have another problem? Perhaps if we start another one from scratch, it will help you understand. I can guide you.

    • one year ago
  24. mmbuckaroos
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    yes one sec sorry

    • one year ago
  25. mmbuckaroos
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    x^3-x^2-4x-6=0

    • one year ago
  26. Mertsj
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    Can you list the possible rational roots?

    • one year ago
  27. Mertsj
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    It is so hard to help someone who won't respond.

    • one year ago
  28. mmbuckaroos
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    Sorry my computer shut down. Ok: +/-1, +/-1/6 ?

    • one year ago
  29. shelovespiano
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    He's not online anymore.... btw. I don't think I can help you, though, sorry:/ bump your question i guess?

    • one year ago
  30. mmbuckaroos
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    It's alright. I think I got it figured out. Feel bad I left him hanging there darn computer for some reason it doesn't ever like this site

    • one year ago
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