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Determine all of the roots of the given equation: x^3-2x^2-3x+10=0

Mathematics
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Complex, too? @mmbuckaroos?
x=-2 x=2-i x=2+i
Could you explaint o me how you got those so I can try my other problems please?

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Other answers:

Sorry, I'm a little low on time... if you bump your question, i'm sure someone else can help you. sorry!
ok thanks
The possible rational roots are the factors of the constant term which is 10 divided by the factors of the coefficient of the term with the highest exponent which is the x^3 term. It's coefficient is 1. So the possible rational roots are: \[\frac{\pm10}{1}, \frac{\pm5}{1}, \pm\frac{2}{1}, \frac{\pm1}{1}\]
Use synthetic division to see if any of those are actually roots.
Since we have reason to believe that -2 is a root, let's try it.
|dw:1335664232988:dw|
So we see that -2 is a root and now we must solve the quadratic equation x^2-4x+5=0 to find the other roots.
ok this is the part that confuses me this division. My book here makes it so confusing
like where do you get all of those numbers from? Sorry I just don't get this at all.
|dw:1335664387666:dw|
So you need help with synthetic division?
Do you understand the part about the possible rational roots?
I actually think I figured out what you did to get those numbers now so nvm on that ? I understand the possible rational roots
So you need help with the synthetic division process?
do i have to do the synthetic division for every possible rational root?
No. Just until you find one where the remainder is 0. That indicates that you have found a factor. Then you can start working on the quotient to find more roots.
so it is a rootif it comes out equaling zero. ok so now that im following you we can keep going sorry about that
|dw:1335664711981:dw|
So since the second factor is a quadratic and it won't factor, we just plug it into the formula to find the roots.
Do you have another problem? Perhaps if we start another one from scratch, it will help you understand. I can guide you.
yes one sec sorry
x^3-x^2-4x-6=0
Can you list the possible rational roots?
It is so hard to help someone who won't respond.
Sorry my computer shut down. Ok: +/-1, +/-1/6 ?
He's not online anymore.... btw. I don't think I can help you, though, sorry:/ bump your question i guess?
It's alright. I think I got it figured out. Feel bad I left him hanging there darn computer for some reason it doesn't ever like this site

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