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anonymous
 4 years ago
Determine all of the roots of the given equation:
x^32x^23x+10=0
anonymous
 4 years ago
Determine all of the roots of the given equation: x^32x^23x+10=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Complex, too? @mmbuckaroos?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Could you explaint o me how you got those so I can try my other problems please?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, I'm a little low on time... if you bump your question, i'm sure someone else can help you. sorry!

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2The possible rational roots are the factors of the constant term which is 10 divided by the factors of the coefficient of the term with the highest exponent which is the x^3 term. It's coefficient is 1. So the possible rational roots are: \[\frac{\pm10}{1}, \frac{\pm5}{1}, \pm\frac{2}{1}, \frac{\pm1}{1}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Use synthetic division to see if any of those are actually roots.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Since we have reason to believe that 2 is a root, let's try it.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So we see that 2 is a root and now we must solve the quadratic equation x^24x+5=0 to find the other roots.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok this is the part that confuses me this division. My book here makes it so confusing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like where do you get all of those numbers from? Sorry I just don't get this at all.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So you need help with synthetic division?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Do you understand the part about the possible rational roots?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I actually think I figured out what you did to get those numbers now so nvm on that ? I understand the possible rational roots

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So you need help with the synthetic division process?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do i have to do the synthetic division for every possible rational root?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2No. Just until you find one where the remainder is 0. That indicates that you have found a factor. Then you can start working on the quotient to find more roots.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it is a rootif it comes out equaling zero. ok so now that im following you we can keep going sorry about that

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So since the second factor is a quadratic and it won't factor, we just plug it into the formula to find the roots.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Do you have another problem? Perhaps if we start another one from scratch, it will help you understand. I can guide you.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Can you list the possible rational roots?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2It is so hard to help someone who won't respond.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry my computer shut down. Ok: +/1, +/1/6 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0He's not online anymore.... btw. I don't think I can help you, though, sorry:/ bump your question i guess?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's alright. I think I got it figured out. Feel bad I left him hanging there darn computer for some reason it doesn't ever like this site
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