A community for students.
Here's the question you clicked on:
 0 viewing
mariomintchev
 3 years ago
i need to see how you solve problem #18
mariomintchev
 3 years ago
i need to see how you solve problem #18

This Question is Closed

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1\[\left({1 \over t}\right)^2 ={1 \over t^2}=t^{2}\]From here, you can use the reverse power rule to integrate, and then evaluate.

iHelp
 3 years ago
Best ResponseYou've already chosen the best response.0answer is D, 1/t^2 = t^2, integral of that is 1/t

mariomintchev
 3 years ago
Best ResponseYou've already chosen the best response.0i know the answer. they give it to me. lol i want to see how you get the answer.

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \int\limits_3^5 t^{2}\;\; dt =\,{1 \over t} \;\;\Big^5_3=\,{1 \over 5} + {1 \over 3}\]From this, you get that the answer is \(2/15\)

mariomintchev
 3 years ago
Best ResponseYou've already chosen the best response.0i dont see how you got 1/t

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \int\limits t^{2} dt = {1 \over 2+1}\cdot t^{2+1}=1 t^{1}=\,{1 \over t}\]

mariomintchev
 3 years ago
Best ResponseYou've already chosen the best response.0ah this is too complex. no easier way to solve this?

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1This is just the reverse of the power rule. In general, \[\large \int\limits x^n\;\; dx ={1 \over n+1}\cdot x^{n+1}\]Where I just used \(n=2\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.