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answer is D, 1/t^2 = t^-2, integral of that is -1/t

i know the answer. they give it to me. lol
i want to see how you get the answer.

i dont see how you got -1/t

\[\large \int\limits t^{-2} dt = {1 \over -2+1}\cdot t^{-2+1}=-1 t^{-1}=-\,{1 \over t}\]

ah this is too complex. no easier way to solve this?