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Determine an equation for the tangent to each curve at the indicated value.
P(x)=(x^3+2)(4x^23),x=3
 one year ago
 one year ago
Determine an equation for the tangent to each curve at the indicated value. P(x)=(x^3+2)(4x^23),x=3
 one year ago
 one year ago

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IsTimBest ResponseYou've already chosen the best response.1
I've already completed 96% of the question. My final answer is y=149x+4481, but the textbook says it is y=1491x+3648
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
I got \(y=1491x+3648\) as well..probably you did something wrong
 one year ago

IsTimBest ResponseYou've already chosen the best response.1
Er...what did you get as your yvalue?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[yy_1 =m(xx_1)\] \[y+825=1491(x3) => y+825=1491x+4473 => y3648=1491x\] \[=> y =1491x+3648\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
hm, want me to explain? or you understand it?
 one year ago

IsTimBest ResponseYou've already chosen the best response.1
How did you get your yvalue? I did this:\[y=((3)^{3}+2)(4(3)^{2}3)\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
The minus is inside the bracket.
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[y=((3)^3+2)(4(3)^23)\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
then the yvalule is \(825\)
 one year ago

IsTimBest ResponseYou've already chosen the best response.1
No, I don't think the minus sign is inside the bracket... My equation is this actually, sorry. \[y=(−(3)^{3}+2)(4(3)^{2}−3)\] I'll try what you said though.
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Hmm..is it \[P(x) = (x^3+2)(4x^23)\] ?
 one year ago

IsTimBest ResponseYou've already chosen the best response.1
Ignore what I said. Thanks. I got it.
 one year ago
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