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IsTim
 3 years ago
Determine an equation for the tangent to each curve at the indicated value.
P(x)=(x^3+2)(4x^23),x=3
IsTim
 3 years ago
Determine an equation for the tangent to each curve at the indicated value. P(x)=(x^3+2)(4x^23),x=3

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IsTim
 3 years ago
Best ResponseYou've already chosen the best response.1I've already completed 96% of the question. My final answer is y=149x+4481, but the textbook says it is y=1491x+3648

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1I got \(y=1491x+3648\) as well..probably you did something wrong

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.1Er...what did you get as your yvalue?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1\[yy_1 =m(xx_1)\] \[y+825=1491(x3) => y+825=1491x+4473 => y3648=1491x\] \[=> y =1491x+3648\]

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1hm, want me to explain? or you understand it?

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.1How did you get your yvalue? I did this:\[y=((3)^{3}+2)(4(3)^{2}3)\]

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1The minus is inside the bracket.

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1\[y=((3)^3+2)(4(3)^23)\]

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1then the yvalule is \(825\)

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.1No, I don't think the minus sign is inside the bracket... My equation is this actually, sorry. \[y=(−(3)^{3}+2)(4(3)^{2}−3)\] I'll try what you said though.

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm..is it \[P(x) = (x^3+2)(4x^23)\] ?

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.1Ignore what I said. Thanks. I got it.
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